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zloy xaker [14]
3 years ago
6

A car gets 40 km per gallon of gasoline. How many gallons of gasoline would the car need to travel 1240 km

Mathematics
2 answers:
sesenic [268]3 years ago
7 0
1 gallon----------40km
x gallon----------1240km
so,1240/40=31 gallon
klasskru [66]3 years ago
6 0
Do 1,240 divided by 40

= 31 gallons
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The difference of sample means of two populations is 108.7, and the standard deviation of the difference in sample means is 32.
charle [14.2K]

Answer: A. The difference of the two means is significant at the 68% confidence level, so the null hypothesis must be rejected.

Step-by-step explanation:

I just got it right on PLATO, so I know it’s 100% correct.

5 0
3 years ago
Write the first 5 terms of the recursive sequence defined below. a1=0 an=2(an-1)²-1, for n>1​
Aleksandr-060686 [28]

Answer:

  • 0, -1, 1, 1, 1

Step-by-step explanation:

<u>Given recursive formula</u>

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7 0
3 years ago
A container shaped as a rectangular prism can hold 756 wooden cube blocks with edge lengths of 13 ft.
pychu [463]

Answer:

the volume of the container is 28\ ft^{3}

Step-by-step explanation:

we know that

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the volume of the container is equal to

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4 0
3 years ago
Read 2 more answers
Plz somebody help. ^_^
pickupchik [31]

Answer:

sin θ =  15/17

Step-by-step explanation:

First we have to know how much the hypotenuse measures.

to take out the hypotenuse we will use pitagoras, with the following formula.

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c1 = 8

c2 = 15

h^2 = 8^2 + 15^2

h^2 = 64 + 225

h = √ 289

h = 17

well to start we have to know the relationships between angles, legs and the hypotenuse.

a: adjacent

o: opposite

h: hypotenuse

sin θ = o/h

cos θ= a/h

tan θ = o/a

we want to know the sin of θ

sin θ = o/h

sin θ =  15/17

5 0
3 years ago
I am lost on what to do
Neko [114]
\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]&#10;\\\\\\&#10;cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\&#10;-----------------------------\\\\&#10;\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\&#10;-----------------------------\\\\&#10;\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}

\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}&#10;\\\\\\&#10;\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}&#10;\\\\\\&#10;\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0
4 0
3 years ago
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