The best and most correct answer among the choices provided by the question is the third choice "It will be a space laboratory for scientists"<span>
The main purpose of the International Space Station<span> is to provide an </span>international<span> laboratory for experiments within the </span>space<span> environment. Which, despite all our technological advances, is nearly impossible to replicate here on Earth.
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I hope my answer has come to your help. God bless and have a nice day ahead!</span>
With time, the classification systems have undergone numerous alterations. Aristotle made the first attempt at classification. He divided plants into three categories: trees, shrubs, and herbs.
On the other side, red blood cell presence or absence was used to categorise animals. The known organisms cannot all be categorised using this technique.
As a result, Linnaeus provided a two-kingdom classification scheme. Kingdom Plantae and kingdom Animalia are its constituent parts. However, this approach did not distinguish between eukaryotes and prokaryotes or between unicellular and multicellular creatures. As a result, there were numerous species that fell outside of the two kingdoms.
Thus, in order to classify the three kingdoms, Ernest Haeckel divided unicellular eukaryotic organisms into a separate kingdom called Protista.
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Answer:
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Answer:
Explanation:
The following code is written in Java. It creates a function that takes in an ArrayList and an int parameter. Then it loops through the array and adds each element into a new array called newList but adds them the number of times that the numRepeats argument states. Output can be seen in the attached image below.
import java.util.ArrayList;
class Brainly{
public static void main(String[] args) {
ArrayList list = new ArrayList();
list.add('a');
list.add('b');
list.add('c');
ArrayList newList = repeatArrayList(list, 3);
System.out.println(newList);
}
public static ArrayList repeatArrayList(ArrayList list, int numRepeats) {
ArrayList newList = new ArrayList();
for (int x = 0; x < numRepeats; x++) {
for (int i = 0; i < list.size(); i++) {
newList.add(list.get(i));
}
}
return newList;
}
}