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3 years ago

What is 4.45 repeating as a decimal

Mathematics

1 answer:

Ugo [173]3 years ago

7 0

Answer:

4.45 is a repeating decimal number and you want to convert it to a fraction or mixed number. When you say 4.45 repeating, you could mean that 5 or 45 is repeating.

Step-by-step explanation:

i gpt it off Google cuz im dumb

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A diameter of a circle has endpoints P(-10,-2) and Q(4,6).

Olenka [21]

The equation for the midpoint is given by:
$P = (\frac{x1 + x2}{2} , \frac{y1 + y2}{2})$
Substituting values we have:
$P = (\frac{-10 + 4}{2} , \frac{-2 + 6}{2})$
$P = (\frac{-6}{2} , \frac{4}{2})$
$P = (-3 , 2)$
We can find the radius of the circle using the equation of distance between points:
$d = \sqrt{(x2-x1)^2 + (y2-y1)^2}$
Substituting values:
$d = \sqrt{(4-(-3))^2 + (6-2)^2}$
$d = \sqrt{(4+3)^2 + (4)^2}$
$d = \sqrt{(7)^2 + (4)^2}$
$d = \sqrt{49 + 16}$
$d = \sqrt{65}$
The equation of the circle is its standard form is:
$(x-xo) ^ 2 + (y-yo) ^ 2 = r ^ 2
$
Where,
(xo, yo): coordinates of the center of the circle
r: radius of the circle
Substituting values:
$(x + 3) ^ 2 + (y-2) ^ 2 = 65
$

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3 years ago

How do you make system equations from a word problem?

astra-53 [7]

Where is the problem tho?

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3 years ago

A sociologist records the annual household income (in thousands of dollars) among a sample of families living in a high-crime ne

Gnoma [55]

Answer:

The lower quartile is $Q_1=33$ thousand dollars.

The median quartile is $Q_2=39$ thousand dollars.

The upper quartile is $Q_3=45$ thousand dollars.

Step-by-step explanation:

The lower quartile is the median value of the lower half of a data set at the 25th percentile of a distribution.

The median quartile is the median value of a data set at the 50th percentile of a distribution.

The upper quartile is the median value of the upper half of a data set at the 75th percentile of a distribution.

To locate each quartile in a data set, we follow four steps:

Step 1: Put the numbers in order: 23, 25, 33, 34, 39, 39, 44, 45, 48, 55

Step 2: The median is given by $\frac{n+1}{2}$ where n is all scores in the data set.

Because n = 10, the median position is $\frac{10+1}{2}=5.5$

The median is the average of the fifth and sixth positioned scores

$Q_2=\frac{39+39}{2} =39$

Step 3: Compute $\frac{n+1}{2}$ where n is all scores below $Q_2$ .

For scores below $Q_2$ , use only 23, 25, 33, 34, 39.

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_1=33$

Step 4: Compute $\frac{n+1}{2}$ where n is all scores above $Q_2$ .

For scores above $Q_2$ , use only 39, 44, 45, 48, 55

Because n = 5, the median position is $\frac{5+1}{2}=3$

The median is the third positioned score: $Q_3=45$

7 0

3 years ago

If ln(2x=y)=x=1 then dy/dx =

umka21 [38]

N(2x+y) = x +1

Differentiate both sides, using the Chain Rule on the left side.
(1 / (2x + y)) * d(2x + y)/dx = 1
(1 / (2x + y)) * (2 + dy/dx) = 1

<span>Rearrange to isolate dy/dx.
</span>

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3 years ago

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lbvjy [14]

To calculate a volume of a rectangle prism, a cabinet we only need to multiply the dimensions it has, those are height, width, deep:
v = (24)(72)(18)
v = 31104 in^3

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3 years ago