Answer: Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.
Step-by-step explanation:
First creating a sample space :
HHHH, HHHT, TTHT, HTTH, THHH, TTTT, TTTH, TTHH, HTHH, HTTT, HHTT, THTH, HHTH, THTT, HTHT, THHT
A fair coin (H - HEAD, T - TAIL)
Probability = (required outcome / possible outcome)
Probability getting exactly two heads in first four flips:
= 6/16 = 3/8
Probability of getting head on both the first and second flips :
= 4/16 = 1/4
Therefore Joe is right, the probability of getting exactly two heads in the four flips is greater than the probability of getting heads on both the first and second flips.
