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Marysya12 [62]
3 years ago
7

(Segment Proofs)

Mathematics
1 answer:
Anni [7]3 years ago
4 0

Answer:

It's proved below

Step-by-step explanation:

We are given;

- K is the midpoint of JL

- M is the midpoint of LN

By definition of mid points, we can say that;

JK = KL and LM = MN

Now, we are given that JK = MN.

Thus, by substitution, we can deduce that; KL = LM

Thus is because JK can be replaced with KL and MN can be replaced with LM.

Thus, it is proved that KL = LM

You might be interested in
What is a possible solution for x+6≥10
ira [324]

Answer:

4,5,6

Step-by-step explanation:

*The sign of ≥ means that it must be greater or equal to 10 in this case

1). 3 isn't a possible solution due to 9 being less than 10

3+6_10

9_10

9<10

2). 4 is a possible solution due to the sum of 4 and 6 being equal to 10

4+6_10

10_10

10=10

3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10

5+6_10

11_10

11>10

4).6 is a possible solution due to the sum of 6 and 6 being larger than 10

6+6_10

12_10

12>10

Hope this helped! (:

6 0
3 years ago
I need help with this math problem!!
Vesnalui [34]
In order to find which one is or isn't, you need to solve for the value of 'x'. 
2x + 15 = 35 
2x = 20
x = 10 

Substitute x =10, into equation. If each side are not the same (i.e. 0=2), then that's the equation that is not equivalent,

Answer is B
Double check this. Chur! :)

Hope this makes sense.


4 0
3 years ago
Xto the 2nd power - 49 = 0
AnnZ [28]

Answer:

7 to the second power... because 7 times is 49 and 49-49 is 0... so 7 to the second power

6 0
3 years ago
PLEASE HELP!!!!<br><br>Math Homework
Finger [1]

You need to add the second number and the answer to get your answer

A. 2

B.6

D.5

F.4

G. 3


8 0
3 years ago
How do you add a fraction with different denomirers
e-lub [12.9K]
Hey there!
When we're adding with different denominators, our goal is to keep the equivalent fraction, but create like denominators.
Let's think of an easier situation. If we have the number 5 and we want an equivalent number, we multiply by one. It's no different with fractions. We want to multiply by some version of one, like 2/2 or 4/4
For example, if we have:
2/8 + 4/6

Our LCM is 24. Therefore, we multiply 2/8 by 3/3:
2/8(3/3) = 6/24

And 4/6 by 4/4:
4/6(4/4) = 16/24

As you can see, we multiplied by versions of 1, so they're still the same fraction.

We have:
16/24 + 6/24 = 22/24 = 11/12

Hope this helps!
5 0
3 years ago
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