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spayn [35]
3 years ago
7

2 1/4 - 1 2/3 as a mixed number?

Mathematics
1 answer:
Gnom [1K]3 years ago
5 0
Answer:

7/12

Step-by-step explanation:

2 1/4 - 1 2/3 =

2 3/12 - 1 8/12 =

7/12
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6/5 of what number is 60
inn [45]

workings...

60/6=10

10x5=50

answer: 50

3 0
4 years ago
The marked price of an article is 30% above it's selling price and the cost price is 35%less than it's marked price. find the di
SashulF [63]

Answer:

Let C be the cost price of the article. Then:

C(1+30%)=marked price

So:

C(1+30%)=C(1.3)

=1.3C

If the article is then marked down 35%, then its’ price would be:

1.3C(1–35%)=1.3C(.65)

=0.845 or 84.5% of its’ cost

Then:

0.845–1=-0.155

or, a 15.5% loss on the item

8 0
4 years ago
The students in the fourth and fifth grades are going to a concert. There are 178 students. Each row has 8 seats. The fifth grad
nexus9112 [7]

Answer:


Step-by-step explanation:  So there are 148 students total and we know the fifth graders filled up 12 rows and since each row has a number of 8 seats we should multiply 8 times 12, which is equal to 96. Now in order to find the number of rows needed for the fourth graders we should first, subtract 178 minus 96; that is equal to 82. Next, we should divide 82 by the number of seats in each row since what we are trying to find id the number of rows needed for the fourth graders. So, we should divide 82 by 8 which is equal to 10. 25.

The number of rows needed is 11 since all students need to have a seat; the answer cannot be 10 because that means a few students would not have a seat.



8 0
3 years ago
Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e
svet-max [94.6K]

ANSWER

y = 2x -4

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

x = 5 +  ln(t)

y =  {t}^{2}  + 5

From the first equation we make t the subject to get;

x - 5 =  ln(t)

t =  {e}^{x - 5}

We put it into the second equation.

y =  { ({e}^{x - 5}) }^{2}  + 5

y =  { ({e}^{2(x - 5)}) }  + 5

We differentiate to get;

\frac{dy}{dx}  = 2 {e}^{2(x - 5)}

At x=5,

\frac{dy}{dx}  = 2 {e}^{2(5 - 5)}

\frac{dy}{dx}  = 2 {e}^{0}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5)

y = 2x - 10 + 6

y = 2x -4

Without eliminating the parameter,

\frac{dy}{dx}  =  \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }

\frac{dy}{dx}  =  \frac{ 2t}{  \frac{1}{t} }

\frac{dy}{dx}  =  2 {t}^{2}

At x=5,

5 = 5 +  ln(t)

ln(t)  = 0

t =  {e}^{0}  = 1

This implies that,

\frac{dy}{dx}  =  2 {(1)}^{2}  = 2

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

y-y_1=m(x-x_1)

y - 6 = 2(x - 5) =

y = 2x -4

5 0
4 years ago
ok so I have a table that goes 6 down then 2 sides, and I have one side done and from the top to bottom its 7-14-21-28-35-42 the
sesenic [268]

Answer:

Huh.....................

4 0
3 years ago
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