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a_sh-v [17]
2 years ago
5

If a system of equations has no solution what does the graph look like

Mathematics
2 answers:
Helen [10]2 years ago
5 0
Blank to be exact ion think that makes since


adell [148]2 years ago
5 0

Answer:

i need 5 point so idkn

Step-by-step explanation:

fbnwejaknfikoewjsfiko ewjfiojew

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What is the value of x?<br> 52°<br> 93°<br> (x + 3)<br> 78°
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

Step One

Find the exterior angle connected to the 93 degree angle. It is also a supplement to 93. Supplementary angles add to 180. Call the exterior angle y

93 + y = 180          Subtract 93 from both sides

y = 180 - 93

y = 87

Step two

Add all the exterior angles. They equal 360

x + 52 + 87 + x + 3 + 78 = 360    Combine the like terms

Step 3

Solve the equation

2x + 220 = 360                            Subtract 220 from both sides

2x  = 360 - 220

2x = 140                                        Divide by 2

x = 70

I don't see that anywhere, but I'm pretty sure I'm right.

4 0
2 years ago
I need help with this question ):
steposvetlana [31]

Answer:

b

Step-by-step explanation:

its b since you have -1 -2 so its x+1 and x+2

will you try to help me on my question i posted to day

5 0
3 years ago
Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch
nikitadnepr [17]
<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult  = $ x

Let us assume the cots of ticket for 1 children  = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) =  3 x

The cost of ticket for 3 children  = 3 x ( Cost of 1 children ticket)  =  3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒  3 x +  3  y < 75  ... (1)

Similarly,  the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children   = 4 y

⇒  2 x +  4  y < 62  ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25   ⇒ x = 25 - y ( substitute in 2)

2 x +  4  y < 62  or, x +  2 y < 31

⇒   25  - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6  = 19

or, x < 19

So, the cost of 1 adult ticket  is x and is less than $19.

The cost of 1 child ticket  is y  and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket  can not be $ 20 and the cost of 1 children ticket is not $ 8.

4 0
3 years ago
Provide a counterexample for the proposition: If n &gt; 3 then n&gt; 5.
MariettaO [177]

Answer:

Your answer would be C: 4

Step-by-step explanation:

Well, I mean, 4 is greater than 3, but is less than 5. Which proves the n > 5 part wrong.

3 0
2 years ago
Find the number of real number solutions for the equation. x2 + 5x + 7 = 0
horsena [70]
X=-1
-1x2 + 5x-1 +7 = 0
-7+7 =0
0=0
6 0
3 years ago
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