<u>1</u> : 3
8
Make the whole number a fraction, by putting it over 1.
<u>1</u> : <u>3</u>
8 1
Turn the second fraction upside down and multiply:
<u>1</u> . <u>1</u> = <u>1 </u>
8 3 24
S = 1/24
18n^6-20n^4+10n^3=
2n^3 (9n^3-10n+5)
Hope this helps :)
Answer:

Step-by-step explanation:
Recall that since X is uniformly distributed over the set [1,4] we have that the pdf of X is given by
if
and 0 otherwise. In the same manner, the pdf of Y is given by
if
and 0 otherwise.
Note that if Y is in the interval (4,5] then Y>X by default. So, in this case we have that P(Y>X| y in (4,5]) = 1. We want to calculate the probability of having Y in that interval . That is
. Thus,
.
We want to proceed as follows. Using the total probability theorem, given two events A, B we have that
In this case, A is the event that Y>X and B is the event that Y is in the interval (4,5].
If we assume that X and Y are independent, then we have that the joint pdf of X,Y is given by
when
. We can draw the region were Y>X and the function h(x,y) is different from 0. (The drawing is attached). This region is described as follows:
and
, then (the specifics of the calculations of the integrals are ommitted)
Thus,

(10/12) / (4/6)...when dividing with fractions, flip what u r dividing by, then multiply
10/12 * 6/4 = 10/8 which reduces to 5/4 or 1 1/4