1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MrMuchimi
3 years ago
15

Ction f(x) = 42% - 100?

Mathematics
1 answer:
Alexandra [31]3 years ago
4 0

Answer:

TO EASY NOW DO IT IN A CALCULATOR!!

Step-by-step explanation:

You might be interested in
Pls help it is due today!!!!!
Aleksandr [31]

Answer:

BRUH THIS WAS ON MY TEST AND BRUH HONESTLY I HAVE NO CLUEE

8 0
3 years ago
Read 2 more answers
(WILL GIVE BRAINLIEST) Find the mean for the data shown below.
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

17+3=20/2

mean=10

3 0
3 years ago
Read 2 more answers
A mirror is 24 inches high and 28 inches wide. The center of the mirror will hang 514 feet from the floor on a wall that is 8 fe
Vanyuwa [196]

The distance from the top of the mirror to the ceiling once the mirror is hung on the wall is 21 inches

The dimension of the mirror is given as:

Height = 24\ in

Width = 28\ in

From the center of the mirror to the floor of the wall, the distance is:

Distance =5\frac14\ ft

So, the distance to the top of the mirror will be:

Top = 5\frac 14\ ft + \frac 12 \times Height

Substitute 24 for height

Top = 5\frac 14\ ft+ \frac 12 \times 24\ in

Top = 5\frac 14\ ft+ 12 \ in

Convert feet to inches

Top = 5\frac 14\times 12\ in+ 12 \ in

Top = 63\ in+ 12 \ in

Top = 75 \ in

The distance from the top of the mirror to the ceiling is the difference between the height of the wall and 75 inches.

So, we have:

Distance = 8\ ft - 75\ in

Convert feet to inches

Distance = 8\times 12\ in - 75\ in

Distance = 96\ in - 75\ in

Distance = 21\ in

Hence, the distance is 21 inches

Read more about lengths at:

brainly.com/question/10545161

3 0
2 years ago
If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3
Nastasia [14]

Given : Angle  < CEB is bisected by EF.

< CEF = 7x +31.

< FEB = 10x-3.

We need to find the values of x and measure of < FEB, < CEF  and < CEB.

Solution: Angle  < CEB is bisected into two angles < FEB and < CEF.

Therefore,   < FEB = < CEF.

Substituting the values of < FEB and < CEF, we get

10x -3 = 7x +31

Adding 3 on both sides, we get

10x -3+3 = 7x +31+3.

10x = 7x + 34

Subtracting 7x from both sides, we get

10x-7x = 7x-7x +34.

3x = 34.

Dividing both sides by 3, we get

x= 11.33.

Plugging value of x=11.33 in < CEF = 7x +31.

We get

< CEF = 7(11.33) +31 =  79.33+31 = 110.33.

< FEB  = < CEF =  110.33 approximately

< CEB = < FEB +  < CEF  = 110.33 +110.33 = 220.66 approximately



7 0
3 years ago
Find <br><img src="https://tex.z-dn.net/?f=%28%20%7B4x%7D%5E%7B2%7D%20%20%2B%203x%29%20%2B%20%28%20%7B7x%7D%5E%7B2%7D%20%20-%205
marishachu [46]

Answer:

11x^2-2x-6

Step-by-step explanation:

(4x^2+3x)+(7x^2-5x-6)= \\\\(4x^2+7x^2)+(3x-5x)-6= \\\\11x^2-2x-6

Hope this helps!

4 0
3 years ago
Other questions:
  • the rop of a table is in the shape of a trpezoid.it has height 1.5 feet and two parallel bases measure 3 feet and 5 feet.what is
    10·1 answer
  • Negative two point five times twenty
    12·2 answers
  • PLEASE HELP DUE IN A 10 MINUTES I WILL GIVE BRAINLEST
    6·2 answers
  • Measured in a map with a scale of 150 miles per inch, the distance from Chicago to Boston is 4.75. How many miles is it from Chi
    11·1 answer
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
    15·2 answers
  • Can someone help me find the missing height?
    15·1 answer
  • How many times can a honeybee beat its wings in 1 hour
    5·2 answers
  • 50 POINTS: Please help thank you so much!! (Image attached) The polygons are similar. Find the values of the variables.
    5·1 answer
  • A water park sells 168 tickets. Each ticket costs $12. What is the total cost of the tickets sold?
    9·2 answers
  • True or False? y = cos x and y = sec x have the same y-intercept.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!