3 years ago

PLEASE HELP LAST WUESTION!

Mathematics

1 answer:

Akimi4 [234]3 years ago

3 0

The answer is 2 square root of 3

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What is the value of x? <br><br> 3x+17=14x-5

Feliz [49]

Answer:

x=2

Step-by-step explanation:

3x+17=14x-5 so...

22=11x (subtract 3x and add 5 to both sides)

2=x (divide both sides by 11)

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3 years ago

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A van has room for 6 students and 2 teachers . How many vans are needed for a total of 48 students and 16 teachers ?

LekaFEV [45]

48 ÷ 6 = 8

16 ÷ 2 = 8

So you need 8 vans

I hope that helps!

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3 years ago

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The weight that can be safely supported by a 2- by6-inch support beam varies inversely with its length. A builder finds that a

maw [93]

800/6=x/16 6x=12800 divide and get 2133 1/3

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3 years ago

Find the slope of the line graphed below

Korolek [52]

Answer:

Slope = 1

Step-by-step explanation:

(x1, y1) = (-5, -3)

(x2, y2) = (-1, 1)

(y2 - y1) / (x2 - x1) = (1 - -3) / (-1 - -5) = 4 / 4 = 1

Slope = 1

4 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

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3 years ago