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3 years ago

13

A horizontal line on a distance-time graph indicates ________.

2 answers:

Kryger [21]3 years ago

7 0

Answer:

The object is at rest.

Step-by-step explanation:

Distance may be defined as the the total path length covered by the object. Speed may be defined as the distance covered by the object per unit time by the body.

The distance time graph indicates the different line on the graph. The distance time graph that has straight line shows that object is at rest and the object is not moving at all.

Thus, the answer is object is at rest.

xxMikexx [17]3 years ago

4 0

A distance-time graph tells us how far an object has moved with time. The steeper the graph, the faster the motion. A horizontal line means the object is not changing its position - it is not moving, it is at rest. A downward sloping line means the object is returning to the start.

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PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

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3 years ago

Which graph shows the following system of equations and its solutions? -0.1x-0.3y=1.2 and 0.2x-0.5y=2

Vera_Pavlovna [14]

Answer:

Option b is the correct answer as both the equations are true for given solution.

Step-by-step explanation:

Given equations are:

-0.1x-0.3y=1.2

0.2x-0.5y=2

We can observe each graph and find the point that is the solution and put the point in the equations to know if that point is the solution

<u>For option A:</u>

(0,4)

Putting x=0 and y = 4 in both equations

$-0.1(0)-0.3(4)=1.2\\0-1.2 =1.2\\-1.2 \neq 1.2\\0.2(0)-0.5(4)=2\\0-2 = 2\\-2 \neq 2$

This is not the correct answer as both equations are not true with this solution

<u>For Option B:</u>

(0,-4)

Putting x = 0 and y = -4 in both equations

$-0.1(0)-0.3(-4)=1.2\\0+1.2 = 1.2\\1.2 = 1.2\\0.2x-0.5y=2\\0.2(0)-0.5(-4) = 2\\2 = 2$

Both equations are true for (0,-4) hence it is the solution of the system.

<u>For Option C:</u>

(4,0)

$-0.1(4)-0.3(0)=1.2\\-0.4-0 = 1.2\\-0.4 \neq 1.2\\0.2x-0.5y=2\\0.2(4)-0.5(0) = 2\\0.8 \neq 2$

Not true for both equations

Hence,

Option b is the correct answer.

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2 years ago

Second to last question, Find I<br> 50 points

ahrayia [7]

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from angle I, we know the opposite side and the hypotenuse. Therefore, we should use sine.

sin(I) = $\frac{\sqrt{39}}{\sqrt{51}}$

To solve, you can use your calculator and the inverse sine function (sin^-1).

I = sin^-1( $\frac{\sqrt{39}}{\sqrt{51}}$ )

I = 61 degrees

Hope this helps!

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podryga [215]

Answer:

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Step-by-step explanation:

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