MN = √2
it comes from √(1^2 + 1^2) = √2 (use phytagoras)
LK = 2 x MN = 2 √2
NK = √(2^2 + 1^2) = √5
ML = NK = √5
so the perimeter
√2 + 2 √2 + √5 + √5
3 √2 + 2 √5
The cost of the mortgage is $81250
<h3>What are interests?</h3>
Interests are percentages of a principal
Given the following parameters
Principal = $65000
Rate = 7% = 0.07
Time = 5 years
<h3>Calculate the interest</h3>
I = PRT/100
I = 65000*0.07*25
I = 16,250
<h3>Determine the cost of the mortgage</h3>
Cost of mortgage = Principal + Interest
Cost of mortgage = 65000 + 16250
Cost of mortgage = 81,250
Hence the cost of the mortgage is $81250
Learn more on mortgage here: brainly.com/question/22846480
The picture will now be 7.5 inches high by 18 inches wide.
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
__
If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
Answer:
e. 0.0072
Step-by-step explanation:
We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .
Let Z = 
~ N(0,1) where, Xbar = mean contents of six randomly
selected bottles
n = sample size i.e. 6
So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)
P(Xbar < 295) = P( < 
) = P(Z < -2.45) = P(Z > 2.45)
Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .
Therefore, option e is correct .
