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Kipish [7]
3 years ago
10

What is the area of Triangle PQR on the grid?

Mathematics
1 answer:
ycow [4]3 years ago
3 0
B IS THE CORRECT ANSWER




(3 \times 4) \div 2 = 12 \div  2 = 6




good luck
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5. What is the equation of the tangent line to the circle x^2+y^2=1 through the point (6,0)?
notka56 [123]

Answer:

There is no tangent line of the given circle at (6, 0).

Step-by-step explanation:

Given equation of the circle,

x^2 + y^2 = 1

∵ equation of a circle is (x-h)^2 +(y-k)^2 = r^2,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6, 6^2 + y^2 = 1

36 + y^2 = 1

y^2 = 1- 36

y= i\sqrt{35}\neq 0

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

3 0
3 years ago
Josh has a drawer full of unmatched socks. There are 3 purple socks, 2 blue socks, 6 black socks, 4 brown socks, 5 yellow socks.
Ratling [72]

Answer:

3/20

Step-by-step explanation:

because there is only 3 purple socks out of 20 socks total

7 0
4 years ago
Is 2/4 less than 2/12
IgorC [24]
No because, when you multiply 2/4 by 3 it'll = 6/12....and 6/12 is greater than 2/12
3 0
3 years ago
!!ONLY TWO QUESTIONS!!
kakasveta [241]

Answer:

The main difference between a vascular and a non-vascular plant is that a vascular plant has vessels that can carry food and water to all the other parts of the plant. the arrangements of the cell in a non-vascular plant is also a lot simpler.

Step-by-step explanation:

I would classify the plant as vascular because vascular plants tend to be really tall and large in comparison to non-vascular plants.

3 0
3 years ago
Eliminate the parameter in the equations x = 5cos(t) – 7 and y = 5sin(t) 9. how can the rectangular equation be described?
Maksim231197 [3]

Recall that for all t,

cos²(t) + sin²(t) = 1

Now,

x = 5 cos(t) - 7   ⇒   (x + 7)/5 = cos(t)

y = 5 sin(t) + 9   ⇒   (y - 9)/5 = sin(t)

so that substituting into the identity above, we get

((x + 7)/5)² + ((y - 9)/5)² = 1

which we can rewrite as

(x + 7)²/25 + (y - 9)²/25 = 1

(x + 7)² + (y - 9)² = 25

and this is the equation of a circle centered at (-7, 9) with radius 5.

3 0
2 years ago
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