25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
m∡1 + m∡2 = 180
Step-by-step explanation:
m∡1 + m∡2 = 180
This is because supplementary means they add up to 180°.
Decimal Form: 0.45
Fraction Form: 45/100 or 9/20
Answer:
B
Step-by-step explanation:
it's more like 10 points
Answer: 9/12 is equivalent to 3/4.
Explanation: 3 times 12 = 36 and 4 times 9 = 36.
Hope this helps!
