Answer:
8/15
Step-by-step explanation:
tangent = opposite/adjacent,
so tan(A) = 8/15
1 - 5x < 24
Hope this helps you
Brainliest would be appreciated
-AaronWiseIsBae
Answer:
0.003981 . . . . moles per liter
Step-by-step explanation:
The concentration of H+ ions in the acid will be ...
10^(-2.4) ≈ 0.003981 . . . . moles per liter
The concentration of H+ ions in the base will be ...
10^-11.2 ≈ 0.000 000 000 006310 . . . . moles per liter
To a few decimal places, the difference is ...
0.003981 . . . . moles per liter
_____
The two numbers differ by about 9 orders of magnitude, so the value of the difference between the larger and the smaller is essentially the value of the larger number. The smaller one, by comparison, can be considered to be zero (for subtraction purposes).
The answer is b. All numbers are natural numbers
<em>The value of b is 14 and the value of c is 65</em>
<h2>
Explanation:</h2>
The quadratic function is a function of the form:
![f(x)=ax^2+bx+c](https://tex.z-dn.net/?f=f%28x%29%3Dax%5E2%2Bbx%2Bc)
Here we know that the leading coefficient
so we reduce our equation to:
![g(x)=x^2+bx+c](https://tex.z-dn.net/?f=g%28x%29%3Dx%5E2%2Bbx%2Bc)
The roots are those values at which ![g(x)=0](https://tex.z-dn.net/?f=g%28x%29%3D0)
So:
![x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\](https://tex.z-dn.net/?f=x%5E2%2Bbx%2Bc%3D0%20%5C%5C%20%5C%5C%20First%20%5C%20root%3A%20%5C%5C%20%5C%5C%20%28-7%2B4i%29%5E2%2Bb%28-7%2B4i%29%2Bc%3D0%20%5C%5C%20%5C%5C%20%28-7%29%5E2-2%287%29%284i%29%2B%284i%29%5E2-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%2049-56i%2B16i%5E2-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%5C%5C%20Simplifying%3A%20%5C%5C%20%5C%5C%2049-56i%2B16%28-1%29-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%2049-56i-16-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%2033-56i-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%5C%5C)
![Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0](https://tex.z-dn.net/?f=Second%20%5C%20root%3A%20%5C%5C%20%5C%5C%20%28-7-4i%29%5E2%2Bb%28-7-4i%29%2Bc%3D0%20%5C%5C%20%5C%5C%20%28-1%29%5E2%287%2B4i%29%5E2%2Bb%28-7-4i%29%2Bc%3D0%20%5C%5C%20%5C%5C%20%287%29%5E2%2B2%287%29%284i%29%2B%284i%29%5E2-7b-4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%2049%2B56i%2B16i%5E2-7b-4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%5C%5C%20Simplifying%3A%20%5C%5C%20%5C%5C%2049%2B56i%2B16%28-1%29-7b-4bi%2Bc%3D0%20%5C%5C%20%5C%5C%2049%2B56i-16-7b-4bi%2Bc%3D0%20%5C%5C%20%5C%5C%2033%2B56i-7b-4bi%2Bc%3D0)
So we have:
![(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}](https://tex.z-dn.net/?f=%281%29%20%5C%2033-56i-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%282%29%20%5C%2033%2B56i-7b-4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%5C%5C%20Subtract%20%5C%202%20%5C%20from%3A%20%5C%5C%20%5C%5C%2033-56i-7b%2B4bi%2Bc-%2833%2B56i-7b-4bi%2Bc%29%3D0%20%5C%5C%20%5C%5C%2033-56i-7b%2B4bi%2Bc-33-56i%2B7b%2B4bi-c%3D0%20%5C%5C%20%5C%5C%20%5C%5C%20Combine%20%5C%20like%20%5C%20terms%3A%20%5C%5C%20%5C%5C%2033-33-56i-56i-7b%2B7b%2B4bi%2B4bi%2Bc-c%3D0%20%5C%5C%20%5C%5C%20-112i%2B8bi%3D0%20%5C%5C%20%5C%5C%20Isolating%20%5C%20b%3A%20%5C%5C%20%5C%5C%20b%3D%5Cfrac%7B112i%7D%7B8i%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7Bb%3D14%7D)
Finding c from (1):
![33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}](https://tex.z-dn.net/?f=33-56i-7b%2B4bi%2Bc%3D0%20%5C%5C%20%5C%5C%20%5C%5C%20Substituting%20%5C%20b%3A%20%5C%5C%20%5C%5C%2033-56i-7%2814%29%2B4%2814%29i%2Bc%3D0%20%5C%5C%20%5C%5C%2033-56i-98%2B56i%2Bc%3D0%20%5C%5C%20%5C%5C%20-65%2Bc%3D0%20%5C%5C%20%5C%5C%20%5Cboxed%7Bc%3D65%7D)
<h2>Learn more:</h2>
Complex conjugate: brainly.com/question/2137496
#LearnWithBrainly