Answer:
First, you write an explicit formula then plug in the value of n in the formula with the term number you are trying to find, in this case the 13th term.
The steps are in the pictures
the final answer is 121 btw
I believe the correct answer is C) Ten times the quantity of a number plus two. Hope this helps! =)
Answer:
or 
Step-by-step explanation:
We use casework on when
and when
.
For the first case,
, we add 9 to both sides to get
.
Dividing both sides by 3 gives

For the second case,
, we add 9 to both sides to get
.
Dividing both sides by 3 gives
.
Checking both cases, we plug in
and
.
For the first case, we have
, which satisfies the equation.
For the second case, we have
, which also satisfies the equation.
This gives us two solutions to the equation;
and
.
6 1/12 would be the answer
Rewriting our equation with parts separated
1/3+5+3/4
Solving the fraction parts
1/3+3/4=?
Find the LCD of 1/3 and 3/4 and rewrite to solve with the equivalent fractions.
LCD = 12
4/12+9/12=13/12
Simplifying the fraction part, 13/12,
13/12=11/12
Combining the whole and fraction parts
5+1+1/12=6 1/12
If a function is defined as

where both
are continuous functions, then
is also continuous where defined, i.e. where 
So, in your case, this function is continous everywhere, except where

To solve this equation, we can use the formula 
It means that, if the leading terms is 1, then the x coefficient is the opposite of the sum of the roots, and the constant term is the product of the roots.
So, we're looking for two terms whose sum is 7, and whose product is 12. These numbers are easily found to be 3 and 4.
So, this function is continuous for every real number different than 3 or 4.