Answer:
perimeter = 36 m
area = 60 m²
Step-by-step explanation:
there is some missing information. for example about the types of the shapes. e.g. if the triangle on the top is an isosceles triangle (2 equal sides). or if the rectangle at the bottom is actually a square with 6 m on all sides. in order to make the sloped side of the top triangle a round, whole number, i assume that the bottom part is a square.
so, the area of this combined shape is the area of the bottom square plus the area of the top triangle.
area square As = 6×6 = 36 m²
so, one side of the triangle is also 6 m, the other is 14-6 = 8 m.
the area of such a right-angled triangle is half of the full rectangle of 6×8.
area triangle At = 6×8/2 = 48/2 = 24 m²
total area = As + At = 36 + 24 = 60 m²
the perimeter of the total shape is the sum of all sides.
so, 14, 6, 6 and ... the baseline/ Hypotenuse of the top triangle.
for that r need the mentioned Pythagoras :
c² = a² + b²
where a and b are the sides, and c is the Hypotenuse (the side opposite of the 90 degree angle).
so, in our case of an isosceles triangle with a 90 degree angle :
c² = 8² + 6² = 64 + 36 = 100
c = 10 m
so, the perimeter is
14+6+6+10 = 36 m
