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Anna007 [38]
3 years ago
8

Find the sum: -21 + (-13) + (-9). A. -43 B. -25 C. 1 D. 4

Mathematics
2 answers:
Akimi4 [234]3 years ago
4 0
The answer is A. -43. All of thos additions of minus values are made substraction afterwards.
Alja [10]3 years ago
3 0
If you would like to solve - 21 + (- 13) + (- 9), you can calculate this using the following steps:

- 21 + (- 13) + (- 9) = - 21 - 13 - 9 = - 43

The correct result would be A. - 43.
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N76 [4]
Use a calculator and divide
8 0
3 years ago
What is the slope of the line that passes through the points (1,7) and (-4,-8)?
Aleksandr [31]

Answer:

D. 3

Step-by-step explanation:

To find the slope of a line, we can use the equation y2-y1/x2-x1=m or slope.

All we can do now is insert the values of the points into the equation.

-8-7/-4-1=m

-15/-5=m

3=m

Thus, the slope is 3.

Hope this helps!

5 0
3 years ago
Read 2 more answers
MATH PLEASEEE I WILL MARK YOU BRAINLIEST!!
USPshnik [31]

Answer:

The second

Step-by-step explanation:

is the correct equation

4 0
3 years ago
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emma will roll two number cubes labeled 1 through 6. She will record the sum of the two numbers after each roll. She will roll t
SashulF [63]

Answer:

75 times

Step-by-step explanation:

First of all let's ook at the 36 possible outcomes and their sums.

2=1,1

3=1,2 2,1

4=1,3 ; 2,2 ; 3,1

5=1,4 ; 2,3 ; 3,2 ; 4,1

6=1,5 ; 2,4 ; 3,3 ; 4,2 ; 5,1

7=1,6 ; 2,5 ; 3,4 ; 4,3 ; 5,2 ; 6,1

8=2,6 ; 3,5 ; 4,4 ; 5,3 ; 6,2

9=3,6 ; 4,5 ; 5,4 ; 6,3

10=4,6 ; 5,5 ; 6,4

11=5,6 ; 6,5

12=6,6

Looking at the above, there are 4 sums equal to 5 out of a total of 36 sums.

Thus, probability of getting a sum equal to 5 is;

P(5) = 5/36

Now,since the cubes are rolled 540 times, number of times a sum equal to 5 will appear will be;

(5/36) x 540 = 75 times

4 0
3 years ago
For the given statement Pn, write the statements P1, Pk, and Pk+1.
Leno4ka [110]

Answer:

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

Step-by-step explanation:

We are given the statement,

P_{n} as 2 + 4 + 6 + . . . + 2n = n(n+1)

That is,

P_{n} as 2 + 4 + 6 + . . . + 2n = \sum_{i=1}^{n}2i

So, we have,

P_{1} = \sum_{i=1}^{1}2i = 2

P_{k} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k = k(k+1)

P_{k+1} = \sum_{i=1}^{k}2i = 2 + 4 + 6 + . . . + 2k + 2(k+1) = (k+1)(k+2)

Thus, we get,

P_{1} =  2

P_{k} = k(k+1)

P_{k+1} = (k+1)(k+2)

7 0
3 years ago
Read 2 more answers
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