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dmitriy555 [2]
4 years ago
13

Displacement is to velocity as_____is to acceleration

Physics
2 answers:
Pavlova-9 [17]4 years ago
4 0

Answer:

Displacement is to velocity as <em>velocity </em>is to acceleration.

Explanation:

Velocity of an object is equal to the change in displacement per unit time. It is given by :

v=\dfrac{d}{t}

d is the displacement and t is the time taken

Acceleration of an object is given by the change in velocity per unit time. It is given by :

a=\dfrac{v-u}{t}

v and u are final and initial velocities

(v-u) is change in velocity

and t is time taken

So, displacement is to velocity as <em>velocity </em>is to acceleration. This is because velocity is related to displacement and similarly acceleration is related to velocity.

sergeinik [125]4 years ago
3 0

Answer:

Velocity.

Explanation:

The answer is velocity because when you make a graph, one axis is acceleration while the other axis is velocity.

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What is the frequency for a beam of electrons orbiting in a field of 4.62 x 10^-3 T? Let the mass of an electrons m = 9.31 x 10^
melisa1 [442]

Frequency: 1.27\cdot 10^8 Hz

Explanation:

The force experienced by an electron in a magnetic field is

F=qvB

where

q=1.6\cdot 10^{-19}C is the electron charge

v is the speed of the electron

B is the strength of the magnetic field

Since the force is perpendicular to the direction of motion of the electron, the force acts as centripetal force, so we can write:

qvB=m\frac{v^2}{r}

where

r is the radius of the orbit

m=9.31\cdot 10^{-31}kg is the mass of the electron

Re-arranging the equation,

\frac{v}{r}=\frac{qB}{m} (1)

We also know that in a circular motion, the speed is equal to the ratio between circumference of the orbit and orbital period (T):

v=\frac{2\pi r}{T}

Substituting into (1),

\frac{2\pi}{T}=\frac{qB}{m}

We also know that 1/T is equal to the frequency f, so

f=\frac{qB}{2\pi m}

In this problem,

B=4.62\cdot 10^{-3}T

Therefore, the frequency of the electrons is

f=\frac{(1.6\cdot 10^{-19})(4.62\cdot 10^{-3})}{2\pi(9.31\cdot 10^{-31})}=1.27\cdot 10^8 Hz

4 0
3 years ago
A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma
Ann [662]

Answer:

Number of electron on the fur will be 5\times 10^{10}electron

Explanation:

We have given net charge on the fur q=8nC=8\times 10^{-9}C

Charge on one electron e=1.6\times 10^{-19}C

Let there are n number of electrons

So ne=8\times 10^{-9}

n\times 1.6\times 10^{-19}=8\times 10^{-9}

n=5\times 10^{10}electron

So number of electron on the fur will be 5\times 10^{10}electron

6 0
3 years ago
Two plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.50
galben [10]

Answer:

The right solution is "4.5\times 10^{-10} \ Cm".

Explanation:

Given that,

q = 0.50 nC

d = 900 mm

As we know,

⇒ P=qd

By putting the values, we get

⇒     =0.50\times 900

⇒     =(0.50\times 10^{-9})\times 0.9

⇒     =4.5\times 10^{-10} \ Cm  

5 0
3 years ago
Read 2 more answers
Which of these should be avoided in order to prevent heart diseases and disorders?
White raven [17]

Answer:

drugs and alcohol

Explanation:

All the others will help your body, while drugs and alcohol will only harm it .

4 0
3 years ago
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A ball is thrown straight down with a speed of Va2.00 from a building 40.00 meters high. How much S time passes before the ball
-Dominant- [34]

Answer:

Option C is the correct answer.

Explanation:

Considering vertical motion of ball:-

Initial velocity, u =  2 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 40 m

We have equation of motion s= ut + 0.5 at²

Substituting

   s= ut + 0.5 at²

    40 = 2 x t + 0.5 x 9.81 x t²

   4.9t²  + 2t - 40 = 0

   t = 2.66 s   or t = -3.06 s

So, time is 2.66 s.

Option C is the correct answer.

6 0
3 years ago
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