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4 years ago

Displacement is to velocity as_____is to acceleration

Physics

2 answers:

Pavlova-9 [17]4 years ago

4 0

Answer:

Displacement is to velocity as <em>velocity </em>is to acceleration.

Explanation:

Velocity of an object is equal to the change in displacement per unit time. It is given by :

$v=\dfrac{d}{t}$

d is the displacement and t is the time taken

Acceleration of an object is given by the change in velocity per unit time. It is given by :

$a=\dfrac{v-u}{t}$

v and u are final and initial velocities

(v-u) is change in velocity

and t is time taken

So, displacement is to velocity as <em>velocity </em>is to acceleration. This is because velocity is related to displacement and similarly acceleration is related to velocity.

sergeinik [125]4 years ago

3 0

Answer:

Velocity.

Explanation:

The answer is velocity because when you make a graph, one axis is acceleration while the other axis is velocity.

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What is the frequency for a beam of electrons orbiting in a field of 4.62 x 10^-3 T? Let the mass of an electrons m = 9.31 x 10^

melisa1 [442]

Frequency: $1.27\cdot 10^8 Hz$

Explanation:

The force experienced by an electron in a magnetic field is

$F=qvB$

where

$q=1.6\cdot 10^{-19}C$ is the electron charge

v is the speed of the electron

B is the strength of the magnetic field

Since the force is perpendicular to the direction of motion of the electron, the force acts as centripetal force, so we can write:

$qvB=m\frac{v^2}{r}$

where

r is the radius of the orbit

$m=9.31\cdot 10^{-31}kg$ is the mass of the electron

Re-arranging the equation,

$\frac{v}{r}=\frac{qB}{m}$ (1)

We also know that in a circular motion, the speed is equal to the ratio between circumference of the orbit and orbital period (T):

$v=\frac{2\pi r}{T}$

Substituting into (1),

$\frac{2\pi}{T}=\frac{qB}{m}$

We also know that 1/T is equal to the frequency f, so

$f=\frac{qB}{2\pi m}$

In this problem,

$B=4.62\cdot 10^{-3}T$

Therefore, the frequency of the electrons is

$f=\frac{(1.6\cdot 10^{-19})(4.62\cdot 10^{-3})}{2\pi(9.31\cdot 10^{-31})}=1.27\cdot 10^8 Hz$

4 0

3 years ago

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma

Ann [662]

Answer:

Number of electron on the fur will be $5\times 10^{10}electron$

Explanation:

We have given net charge on the fur $q=8nC=8\times 10^{-9}C$

Charge on one electron $e=1.6\times 10^{-19}C$

Let there are n number of electrons

So $ne=8\times 10^{-9}$

$n\times 1.6\times 10^{-19}=8\times 10^{-9}$

$n=5\times 10^{10}electron$

So number of electron on the fur will be $5\times 10^{10}electron$

6 0

3 years ago

Two plastic bowling balls, 1 and 2, are rubbed with cloth until they each carry a uniformly distributed charge of magnitude 0.50

galben [10]

Answer:

The right solution is " $4.5\times 10^{-10} \ Cm$ ".

Explanation:

Given that,

q = 0.50 nC

d = 900 mm

As we know,

⇒ $P=qd$

By putting the values, we get

⇒ $=0.50\times 900$

⇒ $=(0.50\times 10^{-9})\times 0.9$

⇒ $=4.5\times 10^{-10} \ Cm$

5 0

3 years ago

Read 2 more answers

Which of these should be avoided in order to prevent heart diseases and disorders?

White raven [17]

Answer:

drugs and alcohol

Explanation:

All the others will help your body, while drugs and alcohol will only harm it .

4 0

3 years ago

Read 2 more answers

A ball is thrown straight down with a speed of Va2.00 from a building 40.00 meters high. How much S time passes before the ball

-Dominant- [34]

Answer:

Option C is the correct answer.

Explanation:

Considering vertical motion of ball:-

Initial velocity, u = 2 m/s

Acceleration , a = 9.81 m/s²

Displacement, s = 40 m

We have equation of motion s= ut + 0.5 at²

Substituting

s= ut + 0.5 at²

40 = 2 x t + 0.5 x 9.81 x t²

4.9t² + 2t - 40 = 0

t = 2.66 s or t = -3.06 s

So, time is 2.66 s.

Option C is the correct answer.

6 0

3 years ago