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horrorfan [7]
4 years ago
15

Which of the following is NOT a force that influences the wind? A. coriolis effect B. magnetic field C. pressure gradient D. fri

ction
Physics
2 answers:
Pavlova-9 [17]4 years ago
7 0
A magnetic field does not have any influence on wind. The Coriolis effect, pressure gradient, and friction do affect wind.

The solution is B.
ch4aika [34]4 years ago
3 0

Answer: B. magnetic field

Explanation:

Wind blows when there is difference in air pressure i.e. in the area having pressure gradient, wind blows from high pressure area to low pressure area. Force of friction slows the speed of the wind. Thus it is responsible for motion of air. Coriolis effect causes the circular motion of the air. The Coriolis effect changes the direction of the wind.

Thus, from the given options, only the magnetic field does not influence the wind. Magnetic field effects the charged particles or magnetic materials not the wind.  

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Can someone solve this problem and explain to me how you got it​
Zarrin [17]

1) The electric force changes by a factor of 25

2) The electric force changes by a factor of 16/9

Explanation:

1)

The magnitude of the electrostatic force between two charges is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, let's call F the initial force between the two charges when they are at a distance of r.

Later, the distance is changed by a factor of 5. Let's assume it has been increased to a factor of 5: so the new distance is

r' = 5r

Therefore, the new force between the charges is:

F' = k' \frac{q_1 q_2}{r'^2}=k' \frac{q_1 q_2}{(5r)^2}=\frac{1}{25}(k' \frac{q_1 q_2}{r'^2})=\frac{F}{25}

So, the force has changed by a factor of 25.

2)

The original force between the two charges is

F=k\frac{q_1 q_2}{r^2}

In this problem, we have:

- The distance between the charges is changed by a factor of 6:

r' = 6r

- The charges are both changed by a factor of 8:

q_1' = 8q_1

q_2' = 8q_2

Substituting into the equation, we find the new force:

F' = k' \frac{q_1' q_2'}{r'^2}=k' \frac{(8q_1) (8q_2)}{(6r)^2}=\frac{64}{36}(k' \frac{q_1 q_2}{r'^2})=\frac{16}{9}F

So, the force has changed by a factor of 16/9.

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

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3 years ago
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Answer:

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