Supplementary Angle. Adjacent Angle.
The radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series. This can be obtained by using ratio test.
<h3>Find the radius of convergence R and the interval of convergence:</h3>
Ratio test is the test that is used to find the convergence of the given power series.
First aₙ is noted and then aₙ₊₁ is noted.
For ∑ aₙ, aₙ and aₙ₊₁ is noted.
= β
- If β < 1, then the series converges
- If β > 1, then the series diverges
- If β = 1, then the series inconclusive
Here aₙ = (n²/n!) xⁿ⁺³ and aₙ₊₁ = ((n+1)²/(n+1)!) xⁿ⁺¹⁺³ = ((n+1)²/(n+1)!) xⁿ⁺⁴
Now limit is taken,
=
=
=
=
= 0 < 1
Since the limit is less than 1 the series is converging.
We get that,
interval of convergence = (-∞, ∞)
radius of convergence R = ∞
Hence the radius of convergence R is ∞ and the interval of convergence is (-∞, ∞) for the given power series.
Learn more about power series here:
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(time to complete)
f=length= some pattern here using length variable
time(length)
the independent variable aka the input is the length & the output is the time it takes or is needed to complete it.
Answer:
C
Step-by-step explanation:
A
(m² - 3m + 2) / (m² - m)
we see due to a little bit of experience with expressions and multiplications of expressions that
(m² - 3m + 2) = (m - 2)(m - 1)
(m² - m) = m(m - 1)
so,
(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m
so, that's not it.
B
(m² - 2m + 1) / (m - 1)
we see again
(m² - 2m + 1) = (m - 1)(m - 1)
so,
(m - 1)(m - 1) / (m - 1) = m - 1
so, that's not it.
C
(m² - m - 2) / (m² - 1)
we see again
(m² - m - 2) = (m - 2)(m + 1)
and
(m² - 1) = (m + 1)(m - 1)
so,
(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)
yes, that is the solution.
D
(2m² - 4m) / (2(m - 2))
2m(m - 2) / (2(m - 2)) = 2m/2 = m
no, that is not a solution.
The remainder of this polynomial is 1.