9514 1404 393
Answer:
(8.49; 225°)
Step-by-step explanation:
The angle is a 3rd-quadrant angle. The reference angle will be ...
arctan(-6/-6) = 45°
In the 3rd quadrant, the angle is 45° +180° = 225°.
The magnitude of the vector to the point is its distance from the origin:
√((-6)² +(-6)²) = √(6²·2) = 6√2 ≈ 8.4859 ≈ 8.49
The polar coordinates can be written as (8.49; 225°).
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<em>Additional comment</em>
My preferred form for the polar coordinates is 8.49∠225°. Most authors use some sort of notation with parentheses. If parentheses are used, I prefer a semicolon between the coordinate values so they don't get confused with an (x, y) ordered pair that uses a comma. You need to use the coordinate format that is consistent with your curriculum materials.
The distance: use absolute value
Between x and 8: x-8
The distance between x and 8: | x-8 |
“is no more than” means it can be that or be less than that, so use ≤
The distance between x and 8 is no more than 4
| x-8 | ≤ 4
Answer:
ok so. wheres the question
Answer:
<em>I think the best answer will be is</em><em> C. 1.3 Good Luck!</em>