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2 years ago

Which of the following describe 8? Select all that apply.

Mathematics

1 answer:

pav-90 [236]2 years ago

8 0

8 is a<u> Natural number, </u><u>Whole number, Integer and Real number</u>

<h3>What is an integer?</h3>

An integer is a number that cannot be expressed as fraction. They are known as whole numbers.

For natural numbers, they are value that starts from 1 and above. Since 8 is greater than 1, hence it is a natural number.

Real number includes both fractions and whole numbers, hence 8 is also a real number.

Based on the explanation, we can conclude that 8 is a<u> Natural number, </u><u>Whole number, Integer and Real number</u>

Learn more on numbers here: brainly.com/question/1746829

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3 years ago

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1 year ago

Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree

kompoz [17]

Answer:

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zero 1 with multiplicity 3.

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Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

$p(x) = (x-1)^3(x-4)^2$

Zero -3 with multiplicity 1:

Considering the previous zeros:

$p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)$

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2 years ago

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Lubov Fominskaja [6]

Answer: $\sqrt{37}$

=====================================

Work Shown:

6x-y = -3 is the same as 6x-y+3 = 0

6x-y+3 = 0 is the form Ax+By+C = 0 with A = 6, B = -1, C = 3.

The distance d that line is from the point (p,q) = (6, 2) is found by the following

$d = \frac{A*p+B*q+C}{\sqrt{A^2+B^2}}\\\\d = \frac{6*6-1*2+3}{\sqrt{6^2+(-1)^2}}\\\\d = \frac{36-2+3}{\sqrt{36+1}}\\\\d = \frac{37}{\sqrt{37}}\\\\d = \frac{37\sqrt{37}}{37}\\\\d = \sqrt{37}\\\\d \approx 6.08276\\\\$

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3 years ago