do 6x8.(theres two x's and two y's)
C.7/20
Hope i helped
let me know if i did not
Step-by-step explanation:
I would go with a or b but one sec let me work it out
The probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Given mean of 30 minutes and standard deviation of 7.5 minutes.
In a set with mean d and standard deviation d. , the z score is given as:
Z=(X-d)/s.
where d is sample mean and s is standard deviation.
We have to calculate z score and then p value from normal distribution table.
We have been given d=30, s=7.5
p value of Z when X=44 subtracted by the p value of Z when X=16.
When X=44,
Z=(44-30)/7.5
=14/7.5
=1.87
P value=0.9686
When X=16
Z=(16-30)/7.5
=-1.87
P Value=0.0314.
Required probability is =0.9686-0.0314
=0.9372
=93.72%
Hence the probability that a randomly selected individual will have a waiting time between 16 and 44 minutes is 93.72%.
Learn more about z test at brainly.com/question/14453510
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To get the answer to this problem, first we have to subtract the marked up cost to the cost of the product. So we first minus 25.3 and 22.25. When we do this, we will get a difference of 3.05. This is the profit that you will earn. So after that, we have to divide 3.05 and 25.30 to get the mark up percentage. When we do this, we will get an answer of 0.12. So in order to convert that into a percentage, we just have to multiply it by 100 and we will get 12%.
