We know that the lace is also what we would call the circumference of the circle.
And we also know that the circumference of a circle is represented by the equation:
.
We then can use the length of the lace (12.56 ft) to solve for the diameter (d) of the rug. Let us solve for that now:
We now know that the diameter of the rug is
4 ft.
<span>{2 x×0 + 10 x = 3 u(t - 12) - (5 δ(t - 4)) x(0) = -1, x×0×0 = -2}
</span><span>{10 x = 3 u(t - 12) - 5 x(0) δ(t - 4) = -1, False}</span>
Isolate the variable by dividing each side by factors that don't contain the variable.
h = −8
Let Fn be the number of ways of arranging such flagpole with the given conditions.
When arranging a flagpole of n feet high, consider the following cases
If the last flag used is a red flag, then the other flags are n-1 foot high, so they can be seen as arranged on a smaller flagpole of n-1 feet high, which can be done in Fn-1 ways.
Similarly, If the last flag used is a gold flag, then the other flags can be seen as arranged on a smaller flagpole of n-1 feet high. This can be done in Fn-1 ways.
If the last flag used is green, the other flags are n-2 feet high, so the flagpole can be arranged in Fn-2 ways.
Using the sum rule, we obtain that Fn = 2Fn-1 + Fn-2 for all n≥3. Listing all the combinations of flags, the initial conditions are F1 = 2 and F2 = 3.
To Learn more about similar flagpole questions:
brainly.com/question/14277535
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This would depend on if we assume this is constant or exponential growth. If it is linear then it would be:
600=3m+300
300=3m
100=m
A=100d+300
A(12)=1500 mi^2
If it is exponential:
600=300r^3
2=r^3
r=2^(1/3)
A=300(2)^(d/3)
A(12)=4800 mi^2