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tankabanditka [31]
3 years ago
5

Happy thanksgiveing <3

Mathematics
1 answer:
kupik [55]3 years ago
7 0

Answer:

ty!

Step-by-step explanation:

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Is 0.12112112112 a rational number?
slega [8]

Answer: Yes

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can someone please help me with this question
zlopas [31]

Answer:

15 kilometers

Step-by-step explanation:

So we know:

For 4 days she runs 1500 meters each day.

For 3 days she runs 3 kilometers each day.

First off, lets convert 1500 meters into kilometers.

There are 1000 meters in a kilometer, so pluggin in 1500 meters:

1500/1000 = 1.5

So for 4 days she runs 1.5 kilometers each day.

Now, to find the total kilometers, we must find multiply the 1.5 kilometers by the 4 days, the 3 kilometers by the 3 days, then add those two together.

So lets do this:

1.5*4 = 6

So she ran 6 kilometers in the first 4 days.

Next we have:

3*3 = 9

So she ran 9 kilometers in the last 3 days.

Now finally add them together:

6 + 9 = 15

So she ran a total of 15 kilometers.

Hope this helps!

7 0
3 years ago
Explain the process for finding the product of two integers
velikii [3]
When you multiply two integers, or in fact any two numbers, you are finding the product of those two numbers;
So finding the product is done through multiplication.
5 0
4 years ago
ginger takes 10 nickels to buy some pencils at the school store. How many cents dies Ginger have to spend
padilas [110]
She had to spend 50 cents... since nickels value at 5 cents, 10 5 cent coins value at 50 cents

Hope this helps
8 0
3 years ago
Read 2 more answers
Simplify.<br><br> 1/cosθ + tan^2θ/cosθ<br><br> • 1 + sinθ<br> • sec^3θ<br> • 1<br> • cos^3θ
olchik [2.2K]

Answer:

I'm guessing the answer is sec³θ

Step-by-step explanation:

I tried this problem and I got 1/cos³θ and clicked cos³θ, but that answer was incorrect. In my lesson, there were the options:

1. sec³θ

2. cos³θ

3.  secθ

I didn't have options 1 + sinθ or 1 as answers. If sec³θ is not the correct answer, please correct me.

8 0
3 years ago
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