A. The distance between the red ant and the black ant is five units.

To represent the red ant,
xr = 3 - t
yr = 2 + 2 t
zr = 6 + 2 t

To represent the black ant,
xb = t/2
yb = 2 + 3 t
zb = 2 + t

To calculate,
at t = 0
xb - xr = -3
yb - yr - 2-2 = 0
zb - zr = 2-6 = -4
Therefore,
d = √(9+16) = √(25) = 5

b. There will be no collision between the two ants.

To calculate,
3 - t = t/2
6 - 2t = t
6 = 3t
t = 2

If t = 2,
2 + 2*2 = 2 + 3*2

4 0

3 years ago

(PLEASE ANSWER!!) a college student completed some courses worth 4 credits and some courses worth 3 credits. the student earned

Ierofanga [76]

The college student took 13 courses of 3 credit hours.

Step-by-step explanation:

Given,

Total credits = 59

Total courses = 18

Let,

Number of 3 credit hour courses = x

Number of 4 credit hour courses = y

According to given statement;

x+y=18 Eqn 1

3x+4y=59 Eqn 2

We will eliminate y to find the number of 3 credit hour courses, therefore,

Multiplying Eqn 1 by 4

$4(x+y=18)\\4x+4y=72\ \ \ Eqn\ 3$

Subtracting Eqn 2 from Eqn 3

$(4x+4y)-(3x+4y)=72-59\\4x+4y-3x-4y=13\\x=13$

The college student took 13 courses of 3 credit hours.

Keywords: linear equation, subtraction

Learn more about linear equations at:

#LearnwithBrainly

5 0

3 years ago

1+123457890134875986​

1+123457890134875986