Find the distance between the two points (5, -3) and (2, 5). Simplify your answer, and write the exact answer in simplest radica
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The solutions to the systems of equations are:
1. (2, 3) (see attachment below). [one solution]
2. no solution
3. (3, 13) [one solution]
<h3>Solution to a System of Equations?</h3>The solution to a system of equations is the x-value and y-value that will make both equations true. It can be found either using a graph, by elimination method, or substitution method as explained below.
1. Using graph to solve y = 2x - 1 and y = 4x - 5:
The solution is the point where both lines intersect which is: (2, 3) (see attachment below). [one solution]
2. Solving using substitution method:
x = -5y + 4 ---> eqn. 1
3x + 15y = -1 ---> eqn. 2
Substitute x = -5y + 4 into eqn. 2
3(-5y + 4) + 15y = -1
-15y + 12 + 15y = -1
-15y + 15y = -1 - 12
0 = -13 (this shows that there is no solution)
3. Using elimination method:
14x = 2y + 16 ---> eqn. 1
5x = y + 2 ---> eqn. 2
1(14x = 2y + 16)
2(5x = y + 2)
14x = 2y + 16 ----> eqn. 3
10x = 2y + 4 -----> eqn. 4
Subtract
4x = 12
x = 12/4
x = 3
Substitute x = 3 into eqn. 2
5(3) = y + 2
15 = y + 2
15 - 2 = y
13 = y
y = 13
The solution is: (3, 13).
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Douglas invested $ 1300 altogether
<em><u>Solution:</u></em>
Let x represent the amount invested in the account paying 14% interest.
Let y represent the amount invested in the account paying 5% interest
He invests three times as much in an account paying 14% as he does in an account paying 5%
Which means,
x = 3y
<em><u>The simple interest is given by formula:</u></em>
Where,
"p" is the principal
"n" is the number of years
"r" is the rate of interest
<em><u>He earns $152.75 in interest in one year from both accounts combined</u></em>
Therefore,
Combined S.I = 152.75
n = 1 year
<em><u>Considering the account earning 14% interest:</u></em>
<em><u>Considering the account earning 5% interest:</u></em>
<em><u>Since, Combined S.I = 152.75</u></em>
Therefore,
0.42y + 0.05y = 152.75
0.47y = 152.75
Divide both sides by 0.47
y = 325
Therefore,
x = 3y
x = 3(325)
x = 975
<em><u>how much did he invest altogether?</u></em>
Amount invested together = x + y = 975 + 325 = 1300
Thus he invested $ 1300 altogether