All categories

2 years ago

What are the last two ?

Mathematics

1 answer:

uysha [10]2 years ago

8 0

Answer:

uhm

Step-by-step explanation:

You might be interested in

cuanto pagaríamos por un libro cuyo precio es de $25 si le aplicamos un descuento del 25% cuanto dinero ahorramos

kotegsom [21]

Tenemos precio de lista de $25 para el libro.

Si aplicamos un descuento del 25%, este descuento representa:

$D=(\frac{25}{100})\cdot25=0.25\cdot25=6.25$

Ahorramos $6.25.

El precio que pagamos el libro es $18.75.

$P=L-D=25-6.25=18.75$

4 0

6 months ago

What is 2*2^3 in expanded form?

katrin2010 [14]

Answer:

Step-by-step explanation:

To solve this question,we will have to understand some symbols in mathematics...

For example,* means ×

/ Means÷

We have so many of them

So back to the question

2*2^3 means 2 multiply by 2 raise to the power of 3

So 2^3 is 8

Therefore,2*8 means 2×8

It equals to 16

Therefore the final answer is 16

I hope you understand it better now

5 0

3 years ago

Help please. Having some trouble with this question

xeze [42]

Answer:

The answer to your question is 55 ft

Step-by-step explanation:

Data

Person's height = 5 ft

Person's shadow = 10 ft

Tree's height = ?

Tree's shadow = 110 ft

- Use the Thales' theorem to solve this problem

Person's height / Person's shadow = Tree's height / Tree's shadow

- Substitution

5 / 10 = x / 110

-Solve for x

x = 5 (110) / 10

-Simplification

x = 550 / 10

-Result

x = 55 ft

-Conclusion

The tree is 55 ft height

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]

Kamila [148]

Use the power rule for differentiation:

$\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)$

You can use this formula if you remember that a root is just a rational exponential:

$\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}$

So, remembering that the derivative of the logarithm is 1/x, you have

$\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}$

Which you can rewrite as

$\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}$

3 0

2 years ago

Find all polar coordinates of point P = (6, 31°). Im really struggling with this problem and I can't seem to find a consistent a

Kaylis [27]

Answer:

1. (6, -329°) (-6, 211°) (-6, -149°)

2. (5, -5π/3) (-5, 4π/3) (-5,-2π/3)

Notice: (+,+),(+,-),(-,+),(-,-).

If we consider angles beyond 360° or 2π, many other names for these points can be determined.

The polar coordinate can be written as (r, θ) = (r, θ + 2nπ) or (r, θ) = [ - r, θ + (2n + 1)π ], where n is any integer

3 0

3 years ago

Read 2 more answers