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kaheart [24]
3 years ago
10

A piece of thread is 52,000 nanometers thick. How many meters thick is the

Mathematics
1 answer:
siniylev [52]3 years ago
5 0

Answer:

0.000052

1 nanometer = .000000001 meters

.000000001 x 52000 = 0.000052

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BEST ANSWER GETS TO BE BRAINLYEST!!!!!
tekilochka [14]

Answer:

  C. 469 in²

Step-by-step explanation:

The net of the object is a rectangle that is 28 inches long and 14 inches wide. Its area is 392 square inches.

In addition, there are two triangles with base 11 inches and height 7 inches. Together, they have the area of a rectangle 7 by 11, or 77 square inches.

The total surface area of the prism is then ...

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The area of a rectangle is the product of its length and width.

The area of a triangle is half the product of its base and height. So, the area of two identical triangles is the product of their base and height.

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<em>Comment on the geometry</em>

This geometry cannot exist as shown. The height of the triangular face is closer to 6.454 inches than to 7 inches.

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4 years ago
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Radda [10]

(1, \sqrt{27})  and (1, - \sqrt{27})

Step-by-step explanation:

Step 1 :

The co ordinates of the given equilateral triangle are A(-2,1) and B(4,1)

The distance between these 2 points is the length of the given triangle

Distance between the 2 points is  \sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} = sqrt (sq(4-(-2)) + sq(1-1)) = 6

Hence the given triangle has 3 equal side of length 6 unit.

Step 2:

The length of the other side should be 6. Let (x,y) be the co-ordinate of the point C

We have then x = 1 (because the perpendicular from C to AB bisects AB we have the point C to have the x co-ordinate as 1)

Also we have the distance between the point B(4,1) and C(1,y) to be 6 as this is an equilateral triangle

Hence \sqrt{(4-1)^{2} + (1-y)^{2 } = 6

=> 9 + 1 + y^{2} -2 y = 6

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=> y = 2± sqrt(4+104) / 2 = 1 ± sqrt(27)

Hence the possible co ordinates of C are (1, \sqrt{27})  and (1, - \sqrt{27})

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4 years ago
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Answer:

its D) x = -8 is correct

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Answer:

Uhh, I guess 24? I don't understand this question

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