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Norma-Jean [14]
3 years ago
13

I NEED HELP ASAP Find the area of the trapezoid by decomposing it into other shapes.

Mathematics
1 answer:
disa [49]3 years ago
7 0

Answer:

Area of the trapezoid is 38 cm²

Step-by-step explanation:

  • Step 1: Area of the trapezoid can be found by decomposing it into 2 triangles and a rectangle.
  • Step 2: Find area of first triangle. Given base = 5 cm and height = 4 cm

Substitute in formula for area of triangle = 1/2 base * height

Area of triangle, A1 = 1/2 * 5 * 4 = 10 cm²

  • Step 3: Find area of rectangle. Given breadth = 4 cm (Same as height of triangles) Length = 6 cm. Substitute in formula for area of rectangle = length * breadth

Area of rectangle, A2 = 4 * 6 = 24 cm²

  • Step 4: Find area of second triangle. Given height = 4 cm (same as the other triangle) and base = 2 cm (8 cm - 6 cm)

Substitute in formula for area of triangle = 1/2 base * height

Area of triangle, A3 = 1/2 * 2 * 4 = 4 cm²

  • Step 5: Calculate total area = A1 + A2 + A3 = 10 + 24 + 4 = 38 cm²
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3 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039

P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313

P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556

85.56% probability that less than 6 of them have a high school diploma

7 0
3 years ago
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