Use the formula a^2+b^2=c^ which is 7.21
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Answer:
A = 1/2 B H area = 1/2 base X height
B = 2 A / H = 2 * 99 / 12 = 16.5 cm
dA / d t = 1/2 * (B dH / dt + H dB / dt)
dB / dt = (2 dA / dt - B dH / dt) / H
dB / dt = (2 * 1.5 cm^2 / min - 16.5 cm * 2 cm / min) / 12 cm
dB / dt = (3 - 33) / 12 cm/min = -2.5 cm/min
Answer:
A = 12 ft
Step-by-step explanation:
Perimeter ( of SQUARE) B = 64
then each side = 64/4 = 16
AREA of SQUARE C = 400
side X side = 400
then side = sqrt 400
Now use Pyhtagorean Theorem to find leg of right triangle that is
side A Side B hypotenuse Side C
A^2 + 16^2 = (sqrt 400)^2
A^2 = 400 - 256
A^2 = 144 then A = 12 Ft
Answer:
Draw a diagram. Then use tan(x) to find the remainder height of the taller building.
Step-by-step explanation:
