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musickatia [10]
2 years ago
10

Evaluate y^5 for y = 1.

Mathematics
1 answer:
kkurt [141]2 years ago
8 0

Answer:

1

Step-by-step explanation:

note that 1^{n} = 1 for any value of n, thus

1^{5} = 1

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the function f(x)= sqrt x is translated left 5 units and up 3 units to create the function g(x). what is the domain of g(x)?
Zinaida [17]

Answer:

x ≥ -5

Step-by-step explanation:

If we have a translation to left c units, we write " x + c " in the function, and

If we have a translation to right c units, we write " x - c" in the function

If we have vertical translation up b units, we "add b to the function", and

If we have vertical translation down b units, we "subtract b to the function"

The parent function is  f(x)=\sqrt{x}

Since translation left 5 units and up 3 units, we can write:

f(x)=\sqrt{x+5} + 3

The domain is affected by the square root sign and we know the number under the square root CANNOT be negative, so we can say:

x + 5 ≥ 0

x ≥ -5

This is the domain.

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3 years ago
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PLEASE HELP WITH THESE TWO WUESTIONS ILL GIVE BRAINIEST AND GIVE YOU PTS
blondinia [14]
The first one is the same amount of points
4 0
2 years ago
What are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x − π) from x = 0 to x = 2π? (1 point) a x = 3 p
Ratling [72]

x-coordinates for the maximum points in any  function  f(x) by f'(x) =0 would be  x = π/2 and x= 3π/2.

<h3>How to obtain the maximum value of a function?</h3>

To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.

we want to find x-coordinates for the maximum points in any  function  f(x) by f'(x) =0

Given f(x)= 4cos(2x -π)

f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi  = k\pi ...  k in Z

In general  x=(k+1)\pi /2

from x = 0 to x = 2π :

when k =0  then  x = π/2

when k =1  then x= π

when k =2  then x= 3π/2

when k =3  then x=2π

Thus, X-coordinates of maximum points are  x = π/2 and x= 3π/2

Learn more about maximum of a function here:

brainly.com/question/13333267

#SPJ4

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2 years ago
What is the square root of 5676??
Vladimir [108]
For this there is no exact square root but the closest it get is about 75.33
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2 years ago
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HELP ASAP I WILL GIVE YOU BRAINLEAST<br><br> WHAT IS THE EQUATION OF THE GRAPH?
siniylev [52]

Problem 1 (on the left)

It appears we have an exponential function curve through the points (0,4) and (1,7)

The general exponential function is of the form

y = a*b^x

The value of 'a' is the y intercept or initial value. So a = 4

Plug in (x,y) = (1,7) to help solve for b

y = a*b^x

y = 4*b^x

7 = 4*b^1

7 = 4b

b = 7/4 = 1.75

Therefore, the function is y = 4*(1.75)^x

  • Plug in x = 0 and you should get y = 4.
  • Plug in x = 1 and you should get y = 7

These two facts help confirm we have the correct exponential equation.

<h3>Answer: y = 4*(1.75)^x</h3>

===========================================================

Problem 2 (on the right)

The steps will follow the same idea as the previous question.

The exponential curve goes through (-1, 120) and (0,40)

We have a = 40 this time due to the y intercept (0,40)

Plug in the coordinates of the other point to find b

y = a*b^x

y = 40*b^x

120 = 40*b^(-1)

120 = 40/b

120b = 40

b = 40/120

b = 1/3

<h3>Answer:  y = 40*(1/3)^x</h3>
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2 years ago
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