D it would be in the 5 thousands but you have to divide pi out of it
Answer:
See explanation
Step-by-step explanation:
1. Given the expression
![\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%20%7D)
Note that
![\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E5%7D%3Dx%5E%7B%5Cfrac%7B5%7D%7B7%7D%7D%20%5C%5C%20%5C%5C%5Csqrt%5B4%5D%7Bx%5E2%7D%3Dx%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
When dividing
by
we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

and the result is ![x^{\frac{3}{14}}=\sqrt[14]{x^3}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B3%7D%7B14%7D%7D%3D%5Csqrt%5B14%5D%7Bx%5E3%7D)
2. Given equation ![3\sqrt[4]{(x-2)^3} -4=20](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%3D20)
Add 4:
![3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%2B4%3D20%2B4%5C%5C%20%5C%5C3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%3D24)
Divide by 3:
![\sqrt[4]{(x-2)^3} =8](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D8)
Rewrite the equation as:

Hence,

<span>40x/64ydivided by 5x/8y would be better written as
</span><span>40x/64y
------------ which in turn would be clearer if written as
</span><span>5x/8y
40x
--------
64y
==========
5x
------
8y
Now invert (5x/8y) and multiply (40x/64y) by your result:
</span> 40x 8 y
-------- * ------ Reducing, we get 8/8, or 1. The answer is 1.
64y 5x
Answer:
794.1 ÷ 76.1= 10.4349.54
Round to the nearest whole number = 6
Round to the nearest tenth=5.6
Round to the nearest Hundredths=5.63
Round to the nearest Thousandth=5.635
Answer:
__2_sides of equal length
__2_acute angels
__0_right angle(s)
_1__obtuse angle
The triangle is _isosceles____and_obtuse____.
Step-by-step explanation:
if this is the right triangle the longest side will be √162≈ 12.7
the longest side is 15 so the vertex angle is obtuse