Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
Answer:
Step-by-step explanation:
Let's see how well I can explain this. 
is the same as a 30 degree angle which is in quadrant 1. If you picture the unit circle, right in the center of it is the origin. If you draw a straight line from 30 degrees and through the center (the origin), you will automatically "connect" with the reference angle of 30 (this is true for ALL angles on the unit circle). This puts us in quadrant 3. In quadrant 3, x is negative and so is y. So the terminal point of the reference angle for 30 degrees has the same exact values, but both of them are negative (again, because both x and y are negative in quadrant 3). I can't see your choices but the one you want looks like this:
Answer:
5/8
Step-by-step explanation:
A T L A N T I C
8 letters, 3 vowels, 5 consonants
5 consonants out of 8 letters = 5/8
Answer:
In a parallelogram, opposite sides are the same length. If PR = ST, then the same would happen for the other sides.
Step-by-step explanation:
