Answer:
after 11.07secs
Step-by-step explanation:
Given the height of an object modeled by the equation
H = 16T² - 1960
The height of the object on the surface of water is zero, hence H = 0
Substitute
0 =16T² - 1960
Swap
16T² - 1960 = 0
16T² = 1960
T² = 1960/16
T² = 122.5
T = 11.07
Hence the rock will hit the surface of the water after 11.07secs
Answer:
maybe the answer is
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Answer:
1. 0, 2 π , π , 2 π/3 , 4 π/3
2. 7 π/6 , 11 π/6
Step-by-step explanation:
1. we want to find the value of theta
Let us represent theta by x for ease of documentation
So we have ;
sin 2x + sin x = 0
Mathematically;
sin 2x = 2sinxcosx
So;
2 sin x cos x + sin x = 0
sin x (2 cos x + 1) = 0
sin x = 0
or
2cos x + 1 = 0
x = arc sin (0)
within the given range;
x = theta = 0 , 2 π , π
For;
2 cos x + 1 = 0
2cos x = -1
cos x = -1/2
cos x = -0.5
x = arc cos (-0.5)
x = 2 π/3 , 4 π/3
2. cos 2 x = 1 + sin x
Mathematically;
cos 2 x = 1-2 sin^2x
let sin x = y
1-2y^2 = 1 + y
y = -2y^2
1 = -2y
y = -1/2
y = -0.5
sin x = y
sin x = -0.5
x = arc sin (-0.5)
x = 7 π/6 , 11 π/6
Answer:
3789
Step-by-step explanation:
Hello :
1 ) the 1 quadrant : the sine, cosine and tangent are <span> positives
2) the 2 </span> quadrant : the sine is positive but cosine and tangent are negatives
3 ) the 3 quadrant : the tangent is positive but cosine and sine are negatives
4 ) the 4 quadrant : the cosine is positive but tangent and sine are negatives
