Question

The coordinates of the vertices of triangle ABC are given in the table. A B C (4,2) (6,7) (13,1) Triangle ABC is reflected across y=−x . What are the vertices of triangle A'B'C'? Enter your answers in the boxes. A': ( , ​ ​) B': ( , ​ ​) C': ( , ​ ​)

Answer 1

Answer:

A'(-2, -4)

B'(-7, -6)

C'(-1, -13)

Step-by-step explanation:

The rule of reflection across y = -x is given by:

$(x, y) \rightarrow (-y, -x)$

As per the statement:

The coordinates of the vertices of triangle ABC are given:

A(4, 2), B(6, 7) and C(13, 1)

Apply the rule of reflection y = -x to triangle ABC:

$A(4, 2) \rightarrow A'(-2, -4)$

$B(6, 7) \rightarrow B'(-7, -6)$

$C(13, 1) \rightarrow C'(-1, -13)$

Therefore,  the vertices of triangle A'B'C are:

A'(-2, -4)

B'(-7, -6)

C'(-1, -13)

Answer 2

A':(-2,-4)
B':(-7,-6)
C':(-1,-13)

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