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marishachu [46]
3 years ago
8

La un concurs de matematica se dau 40 de probleme. Pentr fiecare raspuns corect se acorda 7 puncte, iar pentru fiecare raspuns g

resit se scad 5 puncte.La sfarsit,un elev a obtinut 232 de puncte.Cate raspunsuri corecte si cate raspunsuri gresite a dat elevul?
Mathematics
1 answer:
Ratling [72]3 years ago
6 0

Answer:

a primit 36 ​​corect ane 4 în mod greșit

Step-by-step explanation:

În această întrebare, ne preocupăm să calculăm numărul de răspunsuri corecte și de răspunsuri greșite pe care elevul le-a dat.

În primul rând, începem prin atribuirea de variabile.

Numărul de răspunsuri corecte să fie x în timp ce numărul de răspunsuri greșite să fie y

Deoarece există 40 de probleme în total, aceasta înseamnă că adăugarea ambelor este egală cu 40 matematic,

x + y = 40. ••• (i)

Acum să trecem la partea complicată. Fiecare răspuns corect = +7. Răspunsul corect total este astfel + 7x Fiecare răspuns greșit este = -5. Răspunsul total greșit este astfel -5y Punct total marcat = 232 Aceasta

înseamnă că; 7x -5y = 232 ••••••••• (ii)

De la i, putem spune y = 40 -x să punem acest lucru în ecuație

ii 7x -5 (40-x) = 232

7x - 200 + 5x = 232

12x = 232 + 200 12x = 432 x = 432/12 x = 36 Deoarece y = 40 - x y = 40 - 36 y = 4

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How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
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one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

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so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

6 0
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