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Lena [83]
3 years ago
12

Let f be the function given by f(x)=2cosx+1. what is the approximation for f(1.5)

Mathematics
2 answers:
suter [353]3 years ago
3 0
Function:
f(x) = 2 cos x +1

Note: The values of x should be given in radians.

Therefore;

Substituting for x = 1.5 radians

f(1.5) = 2 Cos 1.5 + 1 ≈ 1.1415
Daniel [21]3 years ago
3 0

Answer:

1.1414

Step-by-step explanation:

Given that f is  a function given by

f(x) =2cosx +1

Here x is taken in radians.

Hence when x =1.5

we have cos 1.5 = 0.0707

2cosx = 0.1414

And hence

2cosx+1=1+0.1414

=1.1414

Thus we get

f(1.5) = 1.1414 apprxy

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gogolik [260]

Answer:

a) The percentage of bone density scores that are significantly high is 2.28%

b) The percentage of bone density scores that are significantly low is 2.28%

c) The percentage of bone density scores that are not significant is 95.44%

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

a. significantly high​ (or at least 2 standard deviations above the​ mean).

This is 1 subtracted by the pvalue of Z = 2.

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

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b. significantly low​ (or at least 2 standard deviations below the​ mean).

pvalue of Z = -2

Z = -2 has a pvalue of 0.0228

2.28% of scores are signicantly low.

c. not significant​ (or less than 2 standard deviations away from the​ mean).

pvalue of Z = 2 subtracted by the pvalue of Z = -2.

Z = 2 has a pvalue of 0.9772

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% of the scores are not significant

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7.6*10^3+2.3*10^5=7600+230000= 237600.

There are 237600 people living in Brooklyn and Staten Island.


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