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2 years ago

Simplify: 7x2 - 31x2-11)

Mathematics

1 answer:

jek_recluse [69]2 years ago

3 0

The solution is -59

First you multiply the numbers witch will give you

14 - 62 -11

Then you subtract it all and get -59

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9n+21−3n−24 simplify

Thepotemich [5.8K]

Alright First you combine the like terms.
9n - 3n = 6n
21 - 24 = -3

Rewrite the simplified equation
6n - 3 = 0

Solve for n
6n = 3
n = 3/6
n = 1/2

Ask if you need more help! :)

6 0

2 years ago

Please can you help me with questions 1-6

Maru [420]

1.) -4x-32 2.) -6x-3 3.) -3n-28 4.) -2x-7 5.) ??? 6.) 4b-2 (I couldn't figure out #5 sorry)

7 0

2 years ago

Read 2 more answers

PLEASE HELP TEST DUE IN 10 MINUTES WILL GIVE BRAINLIEST AND GOOD REVIW!

Eva8 [605]

Answer:

y=3/2(x)+4

Step-by-step explanation:

Because line AB is perpendicular to line BC, the slope of AB is equal to 3/2. Substituting (-2,1) into the new equation gives us "1=3/2(-2)+b" which simplifies to 1=-3+b. This means that b=4.

6 0

2 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

2 years ago

A map is laid out in the standard (x,y) coordinate plane. How long, in units, is an airplane's path on the map as the airplane f

xeze [42]

Answer:

Distance between the points A and B is 15.52 units.

Step-by-step explanation:

It has been given in the question that an airplane flies along a straight line from City A to City B.

Map has been laid out in the (x, y) coordinate plane and the coordinates of these cities are A(20, 14) and B(5, 10).

Distance between two points A'(x, y) and B'(x', y') is represented by the formula,

d = $\sqrt{(x-x')^{2}+(y-y')^{2}}$

So we plug in the values of (x, y) and (x', y') in the formula,

d = $\sqrt{(20-5)^{2}+(14-10)^{2}}$

d = $\sqrt{(15)^{2}+(4)^{2}}$

d = $\sqrt{225+16}$

d = 15.52

Therefore, distance between the points A and B is 15.52 units.

4 0

2 years ago