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Eddi Din [679]
3 years ago
7

Cloud computing is often divided into three levels of services - infrastructure-as-a-service (IAAS), platform-as-a-service (PAAS

), and software-as-a-service (SAAS). What level of service deals primarily with the networks, servers and storage?
Computers and Technology
1 answer:
Alekssandra [29.7K]3 years ago
5 0

Answer:

Infrastructure-as-a-Service

Explanation:

IaaS provides networking components such as backup, security, scaling, data partitioning and other vital computing resources needed. All these services are provided online using high-levels APIs (Application Programming Interface).

IaaS providers make resources available to customers from the equipment installed in data centers.

Therefore, the service that deals with networks, servers, and storage is Infrastructure-as-a-Service (IaaS

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If you do not use the mini toolbar, it remains on the screen. _______________​ Group of answer choices True False
Digiron [165]

Answer:

The answer is "False".

Explanation:

The mini toolbar is a part of the windows and other operating systems, which available on the editing tool. It is also known as a toolbar, that is often shown with the right mouse.

  • This toolbar gives you access to the most popular configuration functions and is shown over the take-down shortcut menu.
  • It validates and becomes successful as you shift the cursor to the mini toolbar.

4 0
3 years ago
The part of the poppet valve that contacts the valve seat is called the A. face. B. margin. C. head. D. stem.
Phantasy [73]
It should be A face, I think
6 0
3 years ago
Read 2 more answers
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
A _____ is an electronic path over which data can travel.
vazorg [7]
A bus is an electrical path which data travels between the different components in an electronic device.                                                                      
5 0
3 years ago
Use the arr field and mystery () method below.
kolezko [41]

Answer:

The sum of all positive even values in arr

Explanation:

We have an array named arr holding int values

Inside the method mystery:

Two variables s1 and s2 are initialized as 0

A for loop is created iterating through the arr array. Inside the loop:

num is set to the ith position of the arr (num will hold the each value in arr)

Then, we have an if statement that checks if num is greater than 0 (if it is positive number) and if num mod 2 is equal to 0 (if it is an even number). If these conditions are satisfied, num will be added to the s1 (cumulative sum). If num is less than 0 (if it is a negative number), num will be added to the s2 (cumulative sum).

When the loop is done, the value of s1 and s2 is printed.

As you can see, s1 holds the sum of positive even values in the arr

7 0
3 years ago
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