This is a right angle triangle problem
drawing a vertical line at from the point where the ramp touches the car park leaves a right angle triangle with the
opposite being 2m
hypothenus being 10m
adjacent unknown
we could use sine
SineO equal to opposite over hypothenus
SineO equal to 2/10
SineO equal to 0.2
O equal to Sine^1(0.2)
O equal to 11 .5
The angle between the ramp and the horizontal is 11.5 degrees
8 is 1/6 of 8/6 = 1 1/3
125 is 5/10 of 625/10 = 62 1/2
32 is 4/10 of 128/10 = 12 4/5
Answer:
74
Step-by-step explanation:
You subtract 43 from 12 you get 31 then you add 43 and 31 you get 74 bye
Answer:
25
Step-by-step explanation:
2x+2+5x+3=180 (angles on a straight line)
7x+5=180
7x=180-5
7x=175
x=25 (dividing both sides by 7)
