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3 years ago

Simplify x^3/x? need help been stuck on this question forever

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

8 0

x^3/x

= x^(3 - 1)

= x^2

Answer

x^2

GREYUIT [131]3 years ago

7 0

Multiply the exponent of x by 3 giving x^3

The answer is

x^3 evaluates to

To divide by x

Divide by x by subtracting the exponents, and keeping the x, to get

The answer is

x^3/x evaluates to

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the sum of two numbers is 45. the greater number is 9 more than the other number. Find each number. use a system of linear equat

SpyIntel [72]

Answer:

18 and 27

Step-by-step explanation:

Let x = first (smaller) number

Let y = second (larger) number

Sum of two numbers is 45:

⇒ x + y = 45

The greater number is 9 more than the other number:

⇒ y = x + 9

Substitute y = x + 9 into x + y = 45 and solve for x:

⇒ x + (x + 9) = 45

⇒ 2x + 9 = 45

⇒ 2x = 36

⇒ x = 18

Substitute found value for x into y = x + 9 and solve for y:

⇒ y = 18 + 9

⇒ y = 27

Therefore, the two numbers are 18 and 27

5 0

2 years ago

Read 2 more answers

A scuba diver descends in the water at a rate of 20 1/2 feet per minute for 2.8 minutes. He immediately changes course when he s

N76 [4]

Answer:

7.4 feet below sea level

Step-by-step explanation:

Assumed the starting point is the sea level 0.

After 2.8 min the diver is at position:

20 1/2 * 2.8 =
20.5 * 2.8 =
57.4 feet below sea level

The position change after next 2 minutes:

25*2 = 50 feet

The position of the diver after 4.8 min:

57.4 - 50 = 7.4 feet below sea level

3 0

3 years ago

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$