Answer:
56 + 53pi
Step-by-step explanation:
<u><em>Area of small circles:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 4 / 2 = 2cm
A = pi (2cm)^2
A = pi (4cm)
A = 4pi
<u><em>Area of large circle:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 14 / 2 = 7cm
A = pi (7cm)^2
A = pi (49cm)
A = 49pi
<u><em>Area of rectangle:</em></u>
Area = width x length
Area = 14cm x 4cm
Area = 56cm
<u><em>Add all three areas:</em></u>
Area of rectangle + large circle + small circle
56cm + 49pi + 4pi = 56cm + 53pi
It's D: (0,0)
This is because when you put 0 in for x your y value will equal 0 and that is one of your answers, so it's the point (0,0)
Yes it does because when you graph it the next point would be (1,0).
Answer:
Step-by-step explanation:
Using pythag a^2+b^2=16^2
16^2=256
and since a=b the equation is 2x^2=256
/ each side by 2
x^2=128
x=sq rt of 128=11.31 roughly
