The equation T^2=A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A
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x = 8, y = 0
y=x-4
y=-x+2
We substitute y=x-4 into the y for y=-
x+2, and we get:
x-4 = -
x+2
+x +
x
x -4 = 2
+4 +4
x = 6
(4)x = 6 (4)
The 4's cross out and we get:
3x = 24
/3 /3
x=8
Not we substitute x(8) into one of our original equations: y=x-4
y=x-4
y=(8)-4
y=4-4
y-0
We get our final answer: (8,0)
Hope that helps!