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3 years ago

What is the distance between parallel lines whose equations are y = 2x + 7 and y = 2x – 3?

Mathematics

1 answer:

malfutka [58]3 years ago

6 0

Answer:

The distance is $\sqrt{20}$ or $2\sqrt{5}$ .

Step-by-step explanation:

Slope of parallel: 2

Slope of perpendicular: -1/2

Pick a point for y =2x + 7. For example (0,7)

Use the perpendicular slope to get to the other line to find the other point of y=2x-3. Look at the screenshot...I got (4,5).

Distance formula $\sqrt{(x_{2}-x_{1} )^{2}+(y_{2} -y_{1})^2 }$

Insert (0,7) and (4,5)

$\sqrt{(0-4)^{2}+(7-5)^2 }$ = $\sqrt{(-4)^{2}+(2)^2 } = \sqrt{(16)+(4)} } = \sqrt{20} = 2\sqrt{5}$

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Next let's change all our minus signs to plus negatives.

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Now let's simplify this by combining like terms.

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Answer:

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Step-by-step explanation:

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3 years ago

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sladkih [1.3K]

Given:

Given that the graph OACE.

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The midpoint of EC can be determined using the formula,

$Midpoint=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

Substituting the coordinates E(2t,0) and C(2p, 2r), we get;

$Midpoint=(\frac{2t+2p}{2},\frac{0+2r}{2})$

Simplifying, we get;

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Dividing, we get;

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Let's say that ST is side b
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Hope this helps!

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