What is the equation of a line passing through (-6, 5) and having a slope of 1/3 ? A. B. C. D. y = 3x + 7
2 answers:
Answer:
Equation of the line is,
y = x/3 + 7
Step-by-step explanation:
It is given that,a line passing through (-6, 5) and having a slope of 1/3
Points to remember
The equation of a line passing through the point (x₁, y₁) with slope m is given by
(y - y1)/(x - x₁) = m
<u>To find the equation of line</u>
here x₁ = -6, y₁ = 5 and m = 1/3
(y - y1)/(x - x₁) = m
(y - 5)/(x - - 6) = 1/3
(y - 5)/(x + 6) =1/3
y = x/3 + 7
Answer:
y = 1/3 x + 7
Step-by-step explanation:
Given; the line is passing through, (-6,5) and the slope is 1/3
We can get its equation;
We would take, a point (x,y) and the given point (-6,5)
Therefore; Since slope = Δy/Δx
Then;
(5-y)/ (-6-x) = 1/3
3(5-y) = -6 -x
15 - 3y = -6 - x
we get;
3y = 6 + x + 15
3y = x + 21
Therefore;
<u>y = 1/3 x + 7</u>
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