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USPshnik [31]
3 years ago
11

Help with this question

Mathematics
2 answers:
den301095 [7]3 years ago
8 0
The answer would be 2 1/4 because 4 can go into 9 twice and you have 1 left over. hoped this helped!
saw5 [17]3 years ago
6 0
9/4 as a mixed number would be 2 1/4 because 4 can go into 9 twice and there would be 1 left over from 8-9, so you put the 1 over the 4.
Good Luck. Have a Good Day
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The height of a triangle is 5 m less than its base. The area of the triangle is 42 m².
SCORPION-xisa [38]
A = (1/2) b * h
h = b - 5
42 = (1/2) * b * (b - 5)
42 = (1/2) * b^2 - 5b
multiply both sides by 2 to clear the fraction (1/2)
2(42) = 2(1/2) *b^2 - 5b
84 = b^2 -5b
Since this is a quadratic equation, subtract 84 from both sides so that it is set = to zero.
b^2 - 5b - 84 = 0
Now factor.
(b - 12)(b + 5) = 0
b - 12 = 0; b = 12
b + 5 = 0; b = -5
You can't have a negative length so the answer is 12m
To check the answer:
A = (1/2) * 12* 7
A = 42 m^2
4 0
3 years ago
nancy spent 7/8 hour working out at the gym she spent 5/7 of that time lifting weights what fraction of an hour did sje spentld
Juli2301 [7.4K]

\frac{9}{56}\\ Fraction of hour was spent by NAncy in lifting weights

Step-by-step explanation:

Time spent at the gym by Nancy = \frac{7}{8}\,hour

Time spent at lifting weights =  \frac{5}{7}\,hour

What fraction of hour she spent in lifting weights?

Solving:

Fraction of hour she spent in lifting weights= Time spend at the gym-Time spent at lifting weights

Fraction of hour she spent in lifting weights=\frac{7}{8}\,hour-\frac{5}{7}\,hour

=\frac{49}{56}-\frac{40}{56}\\=\frac{49-40}{56}\\=\frac{9}{56}\\

So, \frac{9}{56}\\ Fraction of hour was spent by Nancy in lifting weights

Keywords: Word Problems involving Fractions

Learn more about Word Problems involving Fractions at:

  • brainly.com/question/1648978
  • brainly.com/question/1677114
  • brainly.com/question/605571

#learnwithBrainly

7 0
3 years ago
X 20) Becca has 3 times more games than Susan has. Write an algebraic
vova2212 [387]

Answer:

3*x

Step-by-step explanation:

If Becca has 3 times the amount of games as Susan then you would multiply the number of games Susan has by 3. So we can use X (or another letter) to represent the number of games Susan has. Giving us 3*x  

7 0
3 years ago
Please I need help and I need more practice one this please
PSYCHO15rus [73]
? = 30 because your number is increasing by -8 how to figure it out is by taking 14 - 6 = 8
7 0
3 years ago
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
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