1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shutvik [7]
3 years ago
14

Find a formula for the number of patrons as a function of profit.

Mathematics
1 answer:
Solnce55 [7]3 years ago
5 0
Here is my answer. Let just give assumptions. For example,the relationship is linear.Therefore the slope, "m," is the same throughout.
Let us make patrons the independent variable, the two points are: (1314, 11333) and (1544, 13518).
m = (13518-11333)/(1544-1314)
m = 9.5
 
profit = 9.5 patrons (you pick the variable names)
For 1 more patron substitute 1:
profit = 9.5 (1)
profit = 9.5
 
Isolate "patrons" and you get the function based on profit:
patrons = profit/9.5
 
The break even point is for 0 < profit.
0 < profit = 9.5 patrons
0 < 9.5 patrons
0 < patron
You might be interested in
Helppppp PLZZZZZZZZZZZZZZZZZZZZZZ i need help
Olin [163]

Answer/Step-by-step explanation:

A) The temperature in Chicago could be -10*F because -10 is to the right of -13 on the number line.

Higher Temperatures -->

o----------->I

I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I---I

-13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1   0  1   2  3  4  5  6  7  8  9 10

5 0
3 years ago
Read 2 more answers
Determine whether each function is linear or quadratic. Identify the quadratic, linear, and constant terms. g(x)=-2 x²-3(x-2)
valentinak56 [21]

   The function g(x) is a quadratic function:

  • Its quadratic term is -2x²
  • Its linear term is - 3x
  • Its constant is 6

<h3>What are functions?</h3>

 Functions are algebraic expressions that have at least two variables, in order to make their visual representation through a graph and evaluate their behavior.

 This problem deals with linear or quadratic functions, and these differ in the degree of the exponent of the variable:

  1 : linear

  2 : quadratic

  The function:

g(x) = -2x² - 3(x- 2).

g(x) = -2x² - 3x + 6 , we have a quadratic function.

  • Its quadratic term is -2x²
  • Its linear term is - 3x
  • Its constant is 6

Learn more about functions at:

brainly.com/question/28586957

#SPJ4

8 0
1 year ago
Mrs. Linda has 17.16 cups of brownie mix. If each
Alex73 [517]

Answer:

52 brownies

Step-by-step explanation:

If you divide 17.16 by 0.33, you get 52

5 0
3 years ago
Find the distance between the points (4,-2) and (0,10)
vagabundo [1.1K]

We can solve this problem by using the distance formula. The distance formula is: \sqrt{(x_{1}-x)^{2} + (y_{1} - y)^{2}} We can now put in values and solve.

\sqrt{(4-0)^{2} + (-2-10)^{2}}  

\sqrt{16 + 144}

\sqrt{160} 

3 0
3 years ago
How do you use a formula to calculate gradients
gizmo_the_mogwai [7]

.Answer:

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Use any method to solve the system of equations.<br> 3x + 4y = 12<br> 2x + 3y = 10<br> Solve for y.
    8·1 answer
  • a triangular pyramid has a volume of 840 cubic inches. the triangular base has a base length of 20 inches and a height of 21 inc
    6·1 answer
  • Suppose g(m) varies inversely with m and g(m)=3.5 when m=10. What is the value of m when g(m)=10?
    6·1 answer
  • What system of inequalities is represented by the graph?
    12·1 answer
  • I need help now if baby yoda is to live in the next episode in Mandalorian
    13·1 answer
  • A group of scientists studied the amount of erosion at a beach. The scientist determined that the equation y=-0.5x+26 models the
    13·1 answer
  • Urgent i dont have time pllz help thxx
    12·1 answer
  • What is the slope of a line that passes through (2,-5) and (6,-2)​
    10·1 answer
  • Need help with both plz help me it is turn in by 12:10
    12·2 answers
  • Hep look below 50 points
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!