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Lostsunrise [7]
4 years ago
14

Hw 24 area of parallelogram

Mathematics
1 answer:
Papessa [141]4 years ago
7 0

Answer:

<h2>The width, x, of this parallelogram is 16 cm.</h2>

Step-by-step explanation:

In #14, the area of the parallelogram is 528 cm².

This area is also the value of the formula A = L·W:

A = 528 cm² = (33 cm)·W

To determine the width, W, of this parallelogram, we perform the following division:

W = (528 cm²) / (33 cm) = 16 cm

The width, x, of this parallelogram is 16 cm.

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luda_lava [24]

Answer:

No.

Step-by-step explanation:

Plugging in g(x) into f(x), you don't get x. g(x) would need to be = \sqrt{x\frac{-3}{5} }

3 0
3 years ago
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. mrs. opsahl drove 399 miles on 14 gallons of gas. how many miles per gallon did her car get? 0.27 miles per gallon 28.5 miles
Dennis_Churaev [7]

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2 years ago
The riding stables just received an unexpected rush of registrations for the next horse show, and quickly needs to create some a
liraira [26]

Answer:

Maximum added area will be 60,000 ft²

Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

Step-by-step explanation:

Consider the provided information.

There is sufficient funding to rent 1200 feet of temporary chain-link fencing.

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The total length of fencing is 1200 feet that is same as the total perimeter including that shared line down the middle.

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Substitute the value of L in above formula.

A=(600-\frac{3w}{2})\times w\\A=600w-\frac{3w^2}{2}

A=-\frac{3w^2}{2}+600w

The above equation makes a downward parabola.

In order to find the maximum, find the vertex of parabola as shown:

W=\frac{-b}{2a}=\frac{600}{2\times\frac{3}{2}}=200

Hence, the width should be 200 ft in order to get maximum area,

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Now substitute the value of L and W in area formula.

A=300×200=60,000

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Each paddock measure 200 ft by 150 ft, and the paddocks share a 200-ft long side.

5 0
3 years ago
1/2n-17/12=2/3n-13/6
emmasim [6.3K]
1/2/-33+2=62 but I d k
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3 years ago
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5 (i + 2) = 8 (i -1)
Vinil7 [7]
5(i + 2) = 8(i -1)
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-3i = -18
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3 years ago
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