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3 years ago

There are 154 players on 11 teams . How many players are on one team

Mathematics

1 answer:

jarptica [38.1K]3 years ago

7 0

Answer:

there are 14 on a single team

Step-by-step explanation:

154÷11=14

Or you can do this

11 • 14

add 11 14 times you get 154

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ASAP HELP: If a sample proportion is 0.55, which range of possible values best describes an estimate for the population paramete

iris [78.8K]

Answer:

B.(0.4,0.7)

Step-by-step explanation:

We are given that

Sample proportion

$\hat{p}=0.55$

We have to find the range of possible values which describes best an estimate for the population parameter.

Estimate for the population parameter

$\hat{p}\pm Z(SE)$

A.(0.55,0.6)

Difference between 0.55 and 0.55=0

Difference between 0.55 and 0.6=0.05

Difference between 0.55 and 0.55 is not equal to difference between 0.55 and 0.6.

Hence, option A is wrong.

B.(0.4,0.7)

Difference between 0.55 and 0.4=0.15

Difference between 0.55 and 0.7=0.15

Difference between 0.55 and 0.4 is equal to difference between 0.55 and 0.7.

Hence, option B is correct.

C. (0.4,0.69)

Difference between 0.55 and 0.4=0.15

Difference between 0.55 and 0.69=0.14

Difference between 0.55 and 0.4 is not equal to difference between 0.55 and 0.69.

Hence, option C is not correct.

D.(0.5,0.59)

Difference between 0.55 and 0.5=0.05

Difference between 0.55 and 0.59=0.04

Difference between 0.55 and 0.5 is not equal to difference between 0.55 and 0.59.

Hence, option D is not correct.

5 0

3 years ago

The table shows the outputs, y, for different inputs, x:

Akimi4 [234]

A Yes as the x values are all different

B f(x) = 5x + 14

when x = 2 , f(x) = 5(2) + 14 = 24
x = 5, f(x) = 39,
Each value of f(x) is greater than corresponding ones in the function in A.
when x = 9 f(x) = 59 which is greater than for first function ( =12)

First function is a decreasing while f(x) is increasing

C f(x) = 64 = 5x + 14

5x = 64 - 14 = 50

x = 10

8 0

3 years ago

I keep coming up with different answers please help me?

allsm [11]

The answer is 1,600.

3 0

1 year ago

Read 2 more answers

Find the sum of the first 25 terms in this geometric series:<br> 8 + 6 + 4.5...

Ksivusya [100]

Step-by-step explanation:

Given the geometric sequence

8 + 6 + 4.5...

A geometric sequence has a constant ratio and is defined by

$a_n=a_1\cdot r^{n-1}$

$\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}$

$\frac{6}{8}=\frac{3}{4},\:\quad \frac{4.5}{6}=\frac{3}{4}$

$\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}$

$r=\frac{3}{4}$

$\mathrm{The\:first\:element\:of\:the\:sequence\:is}$

$a_1=8$

$\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:$

$a_n=8\left(\frac{3}{4}\right)^{n-1}$

$\mathrm{Geometric\:sequence\:sum\:formula:}$

$a_1\frac{1-r^n}{1-r}$

$\mathrm{Plug\:in\:the\:values:}$

$n=25,\:\spacea_1=8,\:\spacer=\frac{3}{4}$

$=8\cdot \frac{1-\left(\frac{3}{4}\right)^{25}}{1-\frac{3}{4}}$

$\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}$

$=\frac{\left(1-\left(\frac{3}{4}\right)^{25}\right)\cdot \:8}{1-\frac{3}{4}}$

$=\frac{8\left(-\left(\frac{3}{4}\right)^{25}+1\right)}{\frac{1}{4}}$

$\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}$

$=\frac{8\left(-\frac{3^{25}}{4^{25}}+1\right)}{\frac{1}{4}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}$

$=\frac{\left(1-\frac{3^{25}}{4^{25}}\right)\cdot \:8\cdot \:4}{1}$

$\mathrm{Multiply\:the\:numbers:}\:8\cdot \:4=32$

$=\frac{32\left(-\frac{3^{25}}{4^{25}}+1\right)}{1}$

$=\frac{32\cdot \frac{4^{25}-3^{25}}{4^{25}}}{1}$ ∵ $\mathrm{Join}\:1-\frac{3^{25}}{4^{25}}:\quad \frac{4^{25}-3^{25}}{4^{25}}$

$=32\cdot \frac{4^{25}-3^{25}}{4^{25}}$

$=\frac{\left(4^{25}-3^{25}\right)\cdot \:32}{4^{25}}$

$=\frac{2^5\left(4^{25}-3^{25}\right)}{2^{50}}$ ∵ $\mathrm{Factor}\:32:\ 2^5$ , $\mathrm{Factor}\:4^{25}:\ 2^{50}$

$=\frac{4^{25}-3^{25}}{2^{45}}$ ∵ $\mathrm{Cancel\:}\frac{\left(4^{25}-3^{25}\right)\cdot \:2^5}{2^{50}}:\quad \frac{4^{25}-3^{25}}{2^{45}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a\pm \:b}{c}=\frac{a}{c}\pm \frac{b}{c}$

$=\frac{4^{25}}{2^{45}}-\frac{3^{25}}{2^{45}}$

$=32-\frac{3^{25}}{2^{45}}$ ∵ $\frac{4^{25}}{2^{45}}=32$

$=32-0.024$ ∵ $\frac{3^{25}}{2^{45}}=0.024$

$=31.98$

Therefore, the sum of the first 25 terms in this geometric series: 31.98

3 0

3 years ago

the ratio of men to women working for a company is 5 to4 * 225 employees total how many women work for the company

Natali5045456 [20]

63 i believe correct me if i’m wrong somebody. Im possibly WAY off

4 0

3 years ago